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shivu shetty


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i need explaination for this code .....thanks in advance
if true % code end compt=0; T_edge=[0.1 0.2]; threshold=15; [FileName,PathName] = uigetfile('*.*'...

presque 7 ans il y a | 1 réponse | 0

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how can i count these circles
<</matlabcentral/answers/uploaded_files/111743/out.png>>

presque 7 ans il y a | 1 réponse | 0

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i need code for this steps help me plz
<</matlabcentral/answers/uploaded_files/111721/reference%20paper.png>>

presque 7 ans il y a | 1 réponse | 0

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why m not getting clearer circle edges after performing following operations .plz help
clear all; close all; [FileName,PathName] = uigetfile('*.*','Select the image file'); nomfich=[PathName,FileName]; ima...

presque 7 ans il y a | 1 réponse | 0

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hello i need clearer circle after performing the below code help me plz
<</matlabcentral/answers/uploaded_files/111166/input.jpg>> clear all close all [FileName,PathName] = uigetfile('*.*',...

presque 7 ans il y a | 2 réponses | 0

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is this code correct according to this paper? plz help meee
<</matlabcentral/answers/uploaded_files/111171/reference%20paper.png>> clear all [FileName,PathName] = uigetfile('*.*','Sele...

presque 7 ans il y a | 1 réponse | 0

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how to count no of rings in this image in matlab?
<</matlabcentral/answers/uploaded_files/111036/3.jpg>>

presque 7 ans il y a | 1 réponse | 0

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Error using hsv2rgb (line 59) MAP must be a Mx3 array. Error in hsvdwt (line 35) rgbimg=hsv2rgb(hsvimg);
ima = imread('w4.jpg'); HSV = rgb2hsv(ima); H = HSV(:,:,1); S = HSV(:,:,2); V = HSV(:,:,3); SE = strel('line',11,9...

presque 7 ans il y a | 1 réponse | 0

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how to count no of rings in this image. (no of rings= age of the wood)
i want to count no of rings to detect age of the wood help me

presque 7 ans il y a | 1 réponse | 0

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databanao Index exceeds matrix dimensions. Error in databanao (line 18) X=imread(['./mydata/',person_name,'/',personcontents(face_index,1).name]);
datacontents=dir('./mydata'); mainDatabase=cell(0,0); personno=0; imi=0; for person=1:length(datacontents) ...

presque 7 ans il y a | 1 réponse | 0

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