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Question
averaging selected columns and saving to a new file
I have a data file with 1st column - time, 2nd column measurement and third one error. I want to average 1st column, 2nd column...
plus de 7 ans il y a | 1 réponse | 0
1
réponseQuestion
FIt an inverse equation
I want to fit log(y) = 3/log(x) over log(y) vs log(x) plot. I know x and y. Please help me with it.
plus de 7 ans il y a | 1 réponse | 0
1
réponseQuestion
Lomb scargle periodogram error
I was trying to use https://in.mathworks.com/matlabcentral/fileexchange/20004-lomb--lomb-scargle--periodogram but can any...
plus de 7 ans il y a | 1 réponse | 0
0
réponseQuestion
Data folding and binning
Hey.. I have a power spectrum. I want to do time series data folding. Please help me how can it be done? and I ant phase axis to...
plus de 7 ans il y a | 1 réponse | 0
0
réponseQuestion
Sine curve for a given period value.
I want to fit a sine curce to my data for a given period value. How should I do it?
plus de 7 ans il y a | 1 réponse | 0
1
réponseQuestion
save rows and columns to a new file
Hey.. I have a file with two columns. I have to save only those rows in new file for which the 2nd column's numbers are less ...
presque 8 ans il y a | 1 réponse | 0
0
réponseQuestion
Lomb Scargle periodogram calculation
Hey.. I have to find periodicity using lomb scargle periodogram. I tried with the following function: https://in.mathworks.co...
presque 8 ans il y a | 1 réponse | 0
0
réponseQuestion
Error while running the funcyion
While running my function, I am getting following error. PLease help me Error using fit>iFit (line 340) Comple...
presque 8 ans il y a | 1 réponse | 0
1
réponseQuestion
add contraints on parameters defined in function
I have a function: y =x.^a + z.^b For which I wrote a separate function as I neet to fit it over my data. But I want to ad...
presque 8 ans il y a | 1 réponse | 0
1
réponseQuestion
Model fitting with break point
I have a function: y=A(x/xc)^mc for x>xc y=A(x/xc)^mc for x<xc c is the break point in the data which i don't know. mc ...
presque 8 ans il y a | 1 réponse | 0
