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Xizeng Feng


Last seen: environ un mois il y a |  Actif depuis 2021

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how to vectorize a function?
thanks a lot!

environ 2 mois il y a | 0

Question


what is wrong with my calculation?
It hints the expresion was wrong when I solve the equations as follow: >>syms rs xs rp xp >> [xs,xp]=solve(rs*rp^2/(rs^2+(xs+x...

plus de 2 ans il y a | 1 réponse | 0

1

réponse

Question


Why the results are different when use different letters?
I solve same equations in different ketters and got fifferent results as follow: But rs=a, xs=b, rp=c and xp=d. the equations...

plus de 2 ans il y a | 3 réponses | 0

3

réponses

Question


How to draw a ball by plot3?
I am learning the MATLAB,

presque 3 ans il y a | 3 réponses | 0

3

réponses

Question


How to vectorize the function?
I run the following codes and had the result of fplot. But comes also some warning as in the bottom, Can anyone tell me how to...

presque 3 ans il y a | 2 réponses | 0

2

réponses

Question


In the Symbolic toolbox,how to get the results like in the old version
In the symbolic toolbox, the results in newer version are different from the old version. For example: >> syms x >> int(1/(x-...

environ 3 ans il y a | 2 réponses | 0

2

réponses

Question


如何处理符号运算在不同版本的差别
同样的符号运算，在MATLAB的新旧版本里得到的结果是不一样的，比如 >> syms x >> int(1/(x-x^2)) 在新版本里： ans = 2*atanh(2*x - 1) 在旧版本里： ans= log(x)-log(x-1)...

environ 3 ans il y a | 1 réponse | 0

0

réponse

Question


How to multiply 2 arrays by elements
I have 2 arrays of complex numbers and want to get the result of multiply element by element. What can I do? thanks a lot!

environ 3 ans il y a | 1 réponse | 0

1

réponse

Question


how to vectorize a function?
I ran the following and got some reply: >> y=@(x)x^2; >> fplot(y) 警告: 函数处理数组输入时行为异常。要改善性能，请将您的函数正确向量化，以返回大小和形状与输入参数相同的输出。 >...

plus de 3 ans il y a | 2 réponses | 0

2

réponses

Question


What is the prblem?
I run the following sentens and got the warnings, someone can explain them? >> y=@(x)x^2; >> fplot(y) 警告: 函数处理数组输入时行为异常。要改善性能...

plus de 3 ans il y a | 1 réponse | 0

0

réponse