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Soong Wei Kang


Last seen: environ 4 ans il y a Actif depuis 2020

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Phase shift of image
Hi, I need a code that allow me to measure the phase shfit of a image, but i don't know how to code it. May i get some help with...

environ 4 ans il y a | 1 réponse | 0

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Phase change/phase shift in leaf surface moisture
Hi, I am writing a phase retrieval algorithm, I have few different images that represent different milliliter of water on the l...

environ 4 ans il y a | 1 réponse | 0

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Code take forever to run and output
HI, when i was running my code, only the first 2 figure shown up (Figure 1 and Figure 2), the others are not showing up. I run t...

environ 4 ans il y a | 1 réponse | 0

1

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Question


Gerchberg–Saxton Algorithm with error criterion and padding
Hi, I am new to Gerchberg–Saxton Algorithm, I am writing the codes for this algorithm. Unfortunately, I am facing 2 problems tha...

plus de 4 ans il y a | 1 réponse | 0

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Gerchberg–Saxton algorithm/ Fast Fourier transform/ Phase Retreiveal algorithm
Hi, this is my Gerchberg–Saxton algorithm codes that perform fft and ifft with the purpose of retrieve the phase of the images. ...

plus de 4 ans il y a | 1 réponse | 0

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Gerchberg–Saxton algorithm/ Phase Retreiveal algorithm
Hi, does anyone know any Gerchberg–Saxton algorithm or Phase Retreiveal algorithm (for images) that comes with the error functio...

plus de 4 ans il y a | 1 réponse | 0

1

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Question


Gerchberg–Saxton Algorithm
Hi, i am new to fourier transform and I get this codes from file exhange, but there is 1 line of code that i don't understand, i...

plus de 4 ans il y a | 1 réponse | 0

1

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Matrix dimensions must agree.
I keep getting the error message : Matrix dimensions must agree. from the code "A = abs(imgA).*exp(1*(1i*rando*pi)); " May i kn...

plus de 4 ans il y a | 1 réponse | 0

1

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Question


Random phase generator inside a iteration loop
I am writing a phase retrieval codes, I need a random phase generator inside an iteration loop, but i don't really know how to c...

plus de 4 ans il y a | 1 réponse | 0

1

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