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Question
Function to find the more recurrent number
Hye, I have a matrix 1 by (a big number, like 1000), and I would like to extract the element of the matrix that appears most of ...
environ 14 ans il y a | 4 réponses | 0
4
réponsesQuestion
Fsolve more effective.
Hye, I would like to make Fsolve more effective when it solves complex root of complex function, is their a way?
environ 14 ans il y a | 1 réponse | 0
1
réponseQuestion
more than one input in sprintf
Hye, I would like to put two argument in sprintf. I tried: sprintf('mu=%s ,nu/omega=%s',mu1,q) but it doesn't work, on...
plus de 14 ans il y a | 2 réponses | 0
2
réponsesQuestion
The title of a figure
Hye, How could I give a title to a figure that depend on the input of the function that create the figure.
plus de 14 ans il y a | 2 réponses | 2
2
réponsesQuestion
Function producing two figure
Hye, I made a function who gives 6 plot. I know how to post them all in one figure by using subplot. But I would like to post t...
plus de 14 ans il y a | 1 réponse | 0
1
réponseQuestion
Matlab function
*I need to solve a problem, here are my need:* -To find the zeros of a function -The function is complex -The zeros are compl...
plus de 14 ans il y a | 3 réponses | 0
3
réponsesQuestion
Solve DET and ODE faster
[EDIT: 20110617 14:03 CDT - reformat - WDR] Hye I made a set of function, but it is too slow or innacurate. Here are the functi...
plus de 14 ans il y a | 1 réponse | 0
1
réponseQuestion
fsolve
Is there a way to accelerate the fsolve function, with the least lost of precision possible. In: beta(n+1)=fsolve(F,beta(n))
plus de 14 ans il y a | 2 réponses | 0
2
réponsesQuestion
Faster than ODE45
I would like to go faster than ode45 and ode 23 is there a way to change the input in: [t,y]=ode23tb(@Gi,[0.000001;a],[1,0]);...
plus de 14 ans il y a | 1 réponse | 0
1
réponseQuestion
Complex root of nonlinear complex equation containing besselh
I need to find the complex number which will make the real part of the function and the imaginary part, both equals 0. I have ...
plus de 14 ans il y a | 1 réponse | 0
