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Rajeev


Last seen: 13 jours il y a |  Actif depuis 2025

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Can someone rectify this code?
function F = myfun(Q) ks = 0.015/12; % ks of pipe in ft D = [8/12 6/12 8/12 8/12 6/12 6/12 6/12 8/12 6/12 6/12]; % Diameter of...

13 jours il y a | 4 réponses | 0

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