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Question


Euler's Method (Once again)
Hi! I am looking to solve the initial value problem: dy = y*cos(x) y(0) = 1

environ 11 ans il y a | 1 réponse | 0

1

réponse

Question


how can I use Newton's method to find the extremum with error < 10^-4 ?
f = @(x) 20.*exp(-(x-4).^4) + 6.*sin((pi./7).*x) + 0.4.*x + 20 ; df = -80.*exp(-(x-4).^4).*((x-4).^3) + ((6./7).*pi).*cos((...

environ 12 ans il y a | 1 réponse | 0

1

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Réponse apportée
how can i construct the exact Taylor Polynomial of 4th degree around x = 2?
This will then be the correct? EDU>> taylor (exp(x./2)-2.*x.^2+x+10,x,2) I have to give syms x before it will accept the com...

plus de 12 ans il y a | 0

Question


how can i construct the exact Taylor Polynomial of 4th degree around x = 2?
For the function f =@(x) exp(x./2)-2.*x.^2+x+10 how can i construct the exact Taylor Polynomial of 4th degree around x...

plus de 12 ans il y a | 2 réponses | 0

2

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Question


How to estimate derivative = 2?
I want to know how i can use, by knowing a set of x- and y-values, using formulas for finite difference from 1st to 4th degree. ...

plus de 12 ans il y a | 1 réponse | 0

0

réponse

Question


How to make a script to calculate the sum described
100 ∑ i i=1 [EDITED, Jan, formatted, please apply a proper formatting]

plus de 12 ans il y a | 1 réponse | 0

1

réponse

Question


How to proceed using finite difference formulas to estimate f^(k) (2) for k = 1, 2, 3, 4
How to proceed using finite difference formulas to estimate f^(k) (2) for k = 1, 2, 3, 4

plus de 12 ans il y a | 1 réponse | 0

0

réponse

Réponse apportée
How can I make a function plot based on the values listed below?
Excellent!!

plus de 12 ans il y a | 0

Question


How can I make a function plot based on the values listed below?
X Y 0.00000000e+000 1.10000000e+001 2.00000000e-001 1.12251709e+001 4.00000000e-001 1.13014028e+001 ...

plus de 12 ans il y a | 3 réponses | 0

3

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Question


out = x; "Not enough input arguments"
Script: function out = g(x) %g(x) er en funksjon med delt forskrift out = x; n = length (x); for k=1:n i...

plus de 12 ans il y a | 1 réponse | 0

1

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