photo

ash


Actif depuis 2017

Followers: 0   Following: 0

Message

Statistiques

  • Thankful Level 3

Afficher les badges

Feeds

Afficher par

Question


this code of BAT algorithm is not working..function i wrote i last three lines..plz guide me
function [best,fmin,N_iter]=bat_algorithm(para) % Display help help bat_algorithm.m % Default parameters if n...

environ 6 ans il y a | 1 réponse | 0

0

réponse

Question


In the code if i am changing the power of xdata from 0.1 to 0.9 i am getting same coefficient values 0.2000 10.00 10.00 of x1,x2 and x3. please suggest me what changes are required???
xdata =[10.^(-3) 10.^(-2) 10.^(-1) 1 10.^(1) 10.^(2)]; ydata=(0.5012./(xdata.^2+1.8*xdata+2.2 )); fun=@(x)sum(x(1)./((x(2).*xd...

environ 6 ans il y a | 1 réponse | 0

0

réponse

Question


why a coefficient in optimization goes out of the bound???In my problem it is going out of lower bound.
In Interior search optimization for filters, value of one coefficient is equal to lower bound then if i am increasing the order ...

environ 6 ans il y a | 1 réponse | 0

0

réponse

Question


Can i make 3d plot other than surf plot from these three values??? and how???
x=[0.2 0.2 0.5 0.5 0.8 0.9 ]; y=[0.8 0.9 0.8 0.9 0.9 0.5]; z=[0.9329 0.7530 0.9241 0.7058 1.0344 1.1110];

environ 6 ans il y a | 1 réponse | 0

1

réponse

Question


I need all data points of magnitude and phase response of bode plot from figure.
I need all data points of magnitude and phase response of bode plot from figure.i need all coordinates of (mag,freq) and (phase,...

environ 6 ans il y a | 1 réponse | 0

1

réponse

Question


This code is working but in every run i am getting different value of x(1),x(2) and x(3)..kindly solve this problem...its very urgent
xdata =[ 10.^(-5) 10.^(-4) 10.^(-3) 10.^(-2) 10.^(-1) 1] ; ydata=(0.2575./((xdata.^2)+(0.333.*xdata)+1)); parameterized...

environ 6 ans il y a | 1 réponse | 0

1

réponse

Question


this code is giving same values of x irrespective of change in the power of xdata in fun???i am changing power 0.5 to 0.9 no change in output??
xdata =[10.^(-5) 10.^(-4) 10.^(-3) 10.^(-2) 10.^(-1) 1]; ydata=(0.2575./((xdata.^2)+(0.333.*xdata)+1)); fun=@(x)sum(x(1)...

plus de 6 ans il y a | 1 réponse | 0

1

réponse

Question


in every run i am getting different value of x..????
xdata =[ 1 2 3 4 5 6] ; ydata=(1./(xdata.^2+2*xdata+4)); FitnessFunction = @(x) sum((x(1)./(x(2).*xdata.^1.9+x(3).*xdata.^0.9+...

plus de 6 ans il y a | 1 réponse | 0

0

réponse

Question


GA is not working...Function i have written separately calling in main program but not worked??
xdata =[ 1 2 3 4 5 6] ; ydata=(1./(xdata.^2+2*xdata+4)); FitnessFunction = @simple_fitness; numberOfVariables = 3; x =ga(@g...

plus de 6 ans il y a | 1 réponse | 0

1

réponse

Question


i want to plot transfer function G ,how to do it???G=(((0.2274.*(4.7372.*(s).^(1+0.9)+1)))./((9.9944.*(s).^(1+0.9)))+0.3610.*(s).^(0.9)+1))));
G=(((0.2274.*(4.7372.*(s).^(1+0.9)+1)))./((9.9944.*(s).^(1+0.9)))+0.3610.*(s).^(0.9)+1))));

plus de 6 ans il y a | 1 réponse | 0

1

réponse

Question


i am getting error in last line. i want to find the value of x1,x2 and x3. please help me..
xdata =[10.^(-5) 10.^(-4) 10.^(-3) 10.^(-2) 10.^(-1) 1]; fun = @(x)x(1)./((x(2).*(xdata.^(1+0.9)))+x(3).*(xdata.^(0.9))+1);...

plus de 6 ans il y a | 1 réponse | 0

1

réponse

Question


From magnitude response of an analog low pass filter, how to get -3dB frequency in MATLAB
From magnitude response of an analog low pass filter, how to get -3dB frequency in MATLAB

presque 7 ans il y a | 1 réponse | 0

0

réponse

Question


for α=0.2, β=0.5 >>> z= 27.5, for α=0.5, β=0.8 >>> z=17.0 , for α=0.2, β=0.8 >>>z=18.6,i want to get 3-D plot between α,β and Z without writting equation for Z.
for plotting surf ,kindly help me for my question.

presque 7 ans il y a | 1 réponse | 0

1

réponse

Question


this is my code i am getting error with x = simulannealbnd(ObjectiveFunction,X0,ydata,lb,ub). can help me to resolve it
function y = parameterized_objective(x,xdata) y =x(1)./((x(2).*(xdata.^(1+0.9)))+x(3).*(xdata.^(0.9))+1); ydata=(0...

presque 7 ans il y a | 1 réponse | 0

1

réponse