Use Scaled Doubles to Avoid Precision Loss
This example shows how you can avoid precision loss by overriding the data types in your model with scaled doubles.
To open the
ex_scaled_double
model, at the MATLAB® command line, enter:addpath(fullfile(docroot,'toolbox','fixpoint','examples')) ex_scaled_double
In this model:
The Constant block Output data type is
fixdt(1,8,4)
.The Bitwise Operator block uses the
AND
operator and the bit mask0xFF
to pass the input value to the output. Because the Treat mask as parameter is set toStored Integer
, the block outputs the stored integer value, S, of its input. The encoding scheme is V = SQ+B, where V is the real-world value and Q is the stored integer value.
From the Simulink® Apps tab, select Fixed-Point Tool.
In the Fixed-Point Tool, select Collect Ranges > Use current settings. Click Collect Ranges.
The Display block displays
4.125
as the output value of the Constant block. The Stored Integer Display block displays(SI) bin 0100 0010
, which is the binary equivalent of the stored integer value. Precision loss occurs because the output data type,fixdt(1,8,4)
, cannot represent the output value4.1
exactly.Override data types in the model with scaled doubles. In the Fixed-Point Tool, select Collect Ranges > Scaled double-precision. Click Collect Ranges.
The Display block correctly displays
4.1
as the output value of the Constant block. The Stored Integer Display block displays(SI) 65
, which is the binary equivalent of the stored integer value. Because the model uses scaled doubles to override the data typefixdt(1,8,4)
, the compiled output data type changes toflts8_En4
, which is the scaled doubles equivalent offixdt(1,8,4)
.No precision loss occurs because the scaled doubles use a double to hold the stored value and retain information about the specified data type and scaling.
Note
You cannot use a data type override setting of Double-precision because the Bitwise Operator block does not support floating-point data types.