Problem with generating random dice rolls

1 vue (au cours des 30 derniers jours)
Jon
Jon le 28 Oct 2013
Commenté : Image Analyst le 28 Oct 2013
I'm trying to display a vector which shows the probabilty of scoring a total score between 2 - 12 from a certain amount of 2 dice rolls. I know I don't need to use ifs and elseifs but it's in the question. The greatest probability should be for a score of 7, yet I'm not getting it.
n2= 0;
n3 = 0;
n4 = 0;
n5 = 0;
n6 = 0;
n7 = 0;
n8 = 0;
n9 = 0;
n10 = 0;
n11 = 0;
n12 = 0;
a = 0;
while (a <= 499)
a = a + 1;
D = randi(12, 1, 2);
if (D(1) + D(2) == 2)
n2 = n2 + 1;
elseif (D(1) + D(2) == 3)
n3 = n3 + 1;
elseif (D(1) + D(2) == 4)
n4 = n4 + 1;
elseif (D(1) + D(2) == 5)
n5 = n5 + 1;
elseif (D(1) + D(2) == 6)
n6 = n6 + 1;
elseif (D(1) + D(2) == 7)
n7 = n7 + 1;
elseif (D(1) + D(2) == 8)
n8 = n8 + 1;
elseif (D(1) + D(2) == 9)
n9 = n9 + 1;
elseif (D(1) + D(2) == 10)
n10 = n10 + 1;
elseif (D(1) + D(2) == 11)
n11 = n11 + 1;
elseif (D(1) + D(2) == 12)
n12 = n12 + 1;
end
end
A = [n2, n3, n4, n5, n6, n7, n8, n9, n10, n11, n12] * (36/500)

Réponse acceptée

Image Analyst
Image Analyst le 28 Oct 2013
You need to learn how to vectorize! Try this:
numberOfExperiments = 400;
numberOfDice = 2;
rollValues = randi(6, [numberOfDice, numberOfExperiments]);
sumOfRolls = sum(rollValues, 1);
edges = 1:12;
% Get number of each possible sum:
counts = histc(sumOfRolls, edges)
% Convert to percentage.
counts = 100 * counts / sum(counts)
  2 commentaires
Jon
Jon le 28 Oct 2013
Thanks a lot. How does the randi function actually work in this case?
Image Analyst
Image Analyst le 28 Oct 2013
It generates random numbers from 1 to the first argument (6). The second argument is the array size. I had two rows where row 1 is the first die, and row 2 is the second die. I have 400 columns, where each column is one throw of the pair of dice. If you like my solution, Please officially mark it as Accepted.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Creating and Concatenating Matrices dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by