This is what I have:
xA=[0 4 2 1]; wA=struct('name',{'person1' 'person2' 'person3' 'person4'},'num',num2cell(xA)); peopleA={wA.name}; numA=[wA.num]; [idxA,idxA]=max(numA); primeroA=peopleA{idxA} numAA=numA(numA~=max(numA)); [idxxA,idxxA]=max(numAA); segundoA=peopleA{idxxA}
I want to remove the maximum of the word, that is, the word contained in primeroA, in order to be able to calculate the second maximum without the words being rearrenged or altered.

 Réponse acceptée

Andrei Bobrov
Andrei Bobrov le 4 Nov 2013
xA=[0 4 2 1];
name={'person1' 'person2' 'person3' 'person4'};
[a,b] = unique(xA);
out = name(b(end-1));

Plus de réponses (1)

Azzi Abdelmalek
Azzi Abdelmalek le 4 Nov 2013
Modifié(e) : Azzi Abdelmalek le 4 Nov 2013
xA=[0 4 2 1];
wA=struct('name',{'person1' 'person2' 'person3' 'person4'},'num',num2cell(xA));
peopleA={wA.name};
numA=[wA.num];
[idxA,idxA]=sort(numA,'descend');
primeroA=peopleA{idxA(1)}
segundoA=peopleA{idxA(2)}
terceroA=peopleA{idxA(3)}

1 commentaire

Thank you soo much!! You are a genius! I'm sorry..I accepted the wrong answer and I don't know how to unaccept it. But thank you very much!

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