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Problem with Finite Difference Scheme

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Danila Zharenkov
Danila Zharenkov le 6 Nov 2013
Clôturé : MATLAB Answer Bot le 20 Août 2021
Hello, I'm trying to build the finite difference scheme for this task
I build the finite difference scheme like this
The main problem is boundary conditions for theta, because boundary values on its edges don't depend of other counted values. Here is my code, maybe I made a mistake in it?
clc;
clear all;
%constants
r0=0.1;
a=1.01;
b=1;
mu=1;
c=100;
%step-size for r
n=100;
r_max=1;
hr=r_max/n;
r=0:hr:r_max;
nr=max(size(r));
%step-size for theta
m=200;
th_max=2*pi;
hth=th_max/m;
th=0:hth:th_max;
nth=max(size(th));
%step-size for t
l=100;
t_max=5;
ht=t_max/l;
time=0:ht:t_max;
nt=max(size(time));
u=zeros(nr,nth,nt);
v=zeros(nr,nth,nt);
%Initialization
for i=1:nr
for j=1:nth
if ((i*hr<=r0)&&(0<=th(j))&&(th(j)<=pi/6))
u0=0;
elseif ((i*hr<=r0)&&(pi/6<th(j))&&(th(j)<2*pi))
u0=1;
elseif ((i*hr>r0)&&(0<=th(j))&&(th(j)<=2*pi))
u0=0;
end
u(i,j,1)=u0;
end
end
for i=1:nr
for j=1:nth
if ((r(i)<=r0)&&(0<=th(j))&&(th(j)<=pi/6))
v0=1;
elseif ((r(i)<=r0)&&(pi/6<th(j))&&(th(j)<2*pi))
v0=0;
elseif ((r(i)>r0)&&(0<=th(j))&&(th(j)<=2*pi))
v0=0;
end
v(i,j,1)=v0;
end
end
for t=1:nt-1
for i=2:nr-1
for j=2:nth-1
u(i,j,t+1)=u(i,j,t)+ht*((u(i+1,j,t)-2*u(i,j,t)+u(i-1,j,t))/hr^2+(1/(i*hr)))*((u(i+1,j,t)-u(i,j,t))/hr)+(1/(i*hr)^2)*((u(i,j+1,t)-2*u(i,j,t)+u(i,j-1,t)/hth)+u(i,j,t)*(1-u(i,j,t)-c*v(i,j,t)));
v(i,j,t+1)=v(i,j,t)+ht*((v(i+1,j,t)-2*v(i,j,t)+v(i-1,j,t))/hr^2+(1/(i*hr)))*((v(i+1,j,t)-v(i,j,t))/hr)+(1/(i*hr)^2)*((v(i,j+1,t)-2*v(i,j,t)+v(i,j-1,t)/hth)+a*v(i,j,t)*(1-c*u(i,j,t)-b*v(i,j,t)));
%Boundary
u(1,j,t)=u(2,j,t);
u(nr,j,t)=u(nr-1,j,t);
v(2,j,t)=v(1,j,t);
v(nr,j,t)=v(nr-1,j,t);
u(i,nth,t)=u(i,1,t);
v(i,nth,t)=v(i,1,t);
end
end
end

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