Problem of generating 4 sub-images
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I want to divide a color image into 4 sub-images which are also needed to be color images. However, I got the wrong images for my implementation. Please help me. Thanks!
% I= double(imread('2.jpg'));
% [m,n] = size(I);
%
% r = I(:,:,1); % Get the RED matrix
% g = I(:,:,2); % Get the GREEN matrix
% b = I(:,:,3); % Get the BLUE matrix
%
% [m,n] = size(r);
%
% imgr{1} = r(1:m/2, 1:n/2);
% imgr{2} = r(m/2+1:m, 1:n/2);
% imgr{3} = r(1:m/2, n/2+1:n);
% imgr{4}= r(m/2+1:m, n/2+1:n);
%
% imgg{1} = g(1:m/2, 1:n/2);
% imgg{2} = g(m/2+1:m, 1:n/2);
% imgg{3} = g(1:m/2, n/2+1:n);
% imgg{4}= g(m/2+1:m, n/2+1:n);
%
% imgb{1} = b(1:m/2, 1:n/2);
% imgb{2} = b(m/2+1:m, 1:n/2);
% imgb{3} = b(1:m/2, n/2+1:n);
% imgb{4}= b(m/2+1:m, n/2+1:n);
%
% final_image1(:,:,1)= imgr{1};
% final_image1(:,:,2)= imgg{1};
% final_image1(:,:,3)= imgb{1};
%
% final_image2(:,:,1)= imgr{2};
% final_image2(:,:,2)= imgg{2};
% final_image2(:,:,3)= imgb{2};
%
% final_image3(:,:,1)= imgr{3};
% final_image3(:,:,2)= imgg{3};
% final_image3(:,:,3)= imgb{3};
%
% final_image4(:,:,1)= imgr{4};
% final_image4(:,:,2)= imgg{4};
% final_image4(:,:,3)= imgb{4};
%
% filename = {final_image1,final_image2,final_image3,final_image4};
% q={'a1.bmp','a2.bmp','a3.bmp','a4.bmp'};
%
% for i=1:4
% imwrite(filename{i},q{i},'bmp');
% end
0 commentaires
Réponses (3)
Simon
le 14 Nov 2013
Hi!
What exactly is going wrong?
5 commentaires
Simon
le 15 Nov 2013
You do not neccesarily need the "uint8" conversion of "I" upon splitting the image. If "I" was not defined as double before it will automatically be of class uint8 after "imread".
Image Analyst
le 15 Nov 2013
Modifié(e) : Image Analyst
le 15 Nov 2013
Wow, you really like to have a lot of code don't you? You could have done it in far less space simply by using imcrop() as I and David recommended. See demo code that I added in my answer to show you how simple it can be.
Image Analyst
le 14 Nov 2013
Modifié(e) : Image Analyst
le 15 Nov 2013
Why not simply use imcrop() ? It would take far far fewer lines of code.
And when you do n/2, if n is an odd number, you'll get a .5 fraction off the end of the number and that will not let you do 1:n/2, so you need to do
n1 = floor(n/2);
n2 = n1+1;
Then go from 1 to n1 and from n2 to end.
[rows, columns, numberOfColorChannels] = size(rgbImage);
c1 = floor(columns/2); % Middle column
c2 = c1+1;
r1 = floor(rows/2); % Middle row
r2 = r1+1;
upperLeft = imcrop(rgbImage, [1, 1, c1, r1]);
upperRight = imcrop(rgbImage, [c2, 1, c1, r1]);
lowerLeft = imcrop(rgbImage, [1, r2, c1, r1]);
lowerRight = imcrop(rgbImage, [c2, r2, c1, r1]);
See attached for a full blown demo using MATLAB standard demo image.
0 commentaires
David Sanchez
le 15 Nov 2013
I = your_image;
[r c l] = size(I); % image dimensions
r2 = floor(r/2);
c2 = floor(c/2);
I1 = imcrop(I,[1 r2 1 c2];
I2 = imcrop(I,[r2+1 r 1 c2]);
I3 = imcrop(I,[1 r2 1 c2+1 c]);
I4 = imcrop(I,[r2+1 r c2+1 c]);
Voir également
Catégories
En savoir plus sur Quadratic Programming and Cone Programming dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!