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extruct non zeros values and put into a short matrics
1 vue (au cours des 30 derniers jours)
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A =
0 0 0 0 5 0 0 8 0 0 0 0 8
0 0 0 5 0 0 0 8 0 0 0 0 9
0 0 0 5 0 0 0 7 0 0 0 0 8
0 0 0 0 5 0 0 0 8 0 0 0 9
0 0 0 6 0 0 0 8 0 0 0 0 9
0 0 0 5 0 0 0 7 0 0 0 0 8
0 0 0 8 0 0 0 8 0 0 0 0 9
I want to extruch a small matrics (with 3 columns) containing only non zeros values
Results:
5 8 8
5 8 9
5 7 8
5 8 9
6 8 9
5 7 8
8 8 9
ho I can do this smartly?
thanks
1 commentaire
Image Analyst
le 18 Nov 2013
To do it smartly and robustly, you'd check to make sure that there are the same number of zeros in each row. If there aren't you'd need to decide how to handle that, for example, take the first or last three
threeValues = find(oneRow~= 0, 3, 'first'); % Could be empty, 1, 2, or 3 at most.
if length(threeValues) == 3 .... etc.
Réponses (1)
Azzi Abdelmalek
le 18 Nov 2013
Modifié(e) : Azzi Abdelmalek
le 18 Nov 2013
out=cell2mat(arrayfun(@(x) A(x,A(x,:)~=0),(1:size(A,1))','un',0))
%or
n=size(A,1);
B=zeros(n,3);
for k=1:n
B(k,:)=A(k,A(k,:)~=0);
end
B
2 commentaires
The Matlab Spot
le 18 Nov 2013
this is good...
out=cell2mat(arrayfun(@(x) A(x,A(x,:)~=0),(1:size(A,1))','un',0))
Azzi Abdelmalek
le 18 Nov 2013
Not necessary, the second using for loop is slightly faster then arrayfun
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