How can i see the element of the a cell element of 8*8*8?

Given A is 35*35*35 cell, each cell contains a matrix of 8*8*8 [double]. For each matrix, elements are either 1 or 0. (It means 512 elements in each matrix)

• A is [35* 35*35 cell]
• A(1) is [8*8*8 double] If i want to see a designated cell says A(159) and count the number of one for each matrix How can i see this?

1. If i want to see a designated cell says A(159) and count the number of one for each matrix How can i see this?

• I tried "A(159)" gives me [8x8x8 double] but i want to see all 512 elements.
• Some background information: A big 3d matrix is cut and form cells. I want to perform 3d dct for each cell. but before that, i want to count the ones in each cells first as there are many equal cells, for example a cell with all 512 zeros. If I can find all zero cell, I can reduce the complexity of 3d dct.

Please also provide some codes, thank you

Answer 1

[Azzi Abdelmalek]

a=A{159};
out=sum(a(:))

[ting]

Thank you

Answer 2

[Image Analyst]

Simply have A{159} all by itself on a command line to see the values

A{159}

Then to count the number of elements of each value you can use hist() or histc(). If you have specific values in mind, use sum

numberOfOnes = sum(A{159} == 1);
numberOfZeros = sum(A{159} == 0);
% Count number of non-zeros
if nnz(A{159}) == 0
  % Array is all zeros, so now can simplify.
  % Your code to simplify
end