line of code help!
4 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I was wondering if someone could help me diagnose what the 3rd to last line of code - y{jj,ii}(:,(ii+1):end) = x{jj}(:,(ii+1):end); -- does for this block.
for jj = 1:N
y{jj,1} = ones(N+1);
y{jj,1}(:,2:end) = x{jj}(:,2:end);
A(jj,1) = det(y{jj,1});
y{jj,ii} = ones(N+1);
y{jj,ii}(:,1:(ii-1)) = x{jj}(:,1:(ii-1));
y{jj,ii}(:,(ii+1):end) = x{jj}(:,(ii+1):end);
A(jj,ii) = det(y{jj,ii});
end
0 commentaires
Réponses (1)
dpb
le 3 Déc 2013
for jj = 1:N
...
y{jj,ii}(:,1:(ii-1)) = x{jj}(:,1:(ii-1));
y{jj,ii}(:,(ii+1):end) = x{jj}(:,(ii+1):end);
...
end
Just loading the columns of the array from (ii+1)th to the last similarly as does the preceding line load from the first column to the (ii-1)th. The two lines together load all columns excepting for ii.
doc end
if it's that that's confusing -- it's a builtin that's position-sensitive as to what it returns, specifically.
0 commentaires
Voir également
Catégories
En savoir plus sur Schedule Model Components dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!