Hi,
I made a 2d matrix with two for loops:
for k = 1:32
for l = 1:32
P_new(l,k) = P_old(l) + (LODF(l,k) * P_old(k));
end
end
P_old is here a 32 x 1 matrix and LODF is a 32 x 32 matrix which is already computed. How can I vectorize this code to avoid the for loops? Thanks in advance.

 Réponse acceptée

Matt J
Matt J le 10 Déc 2013

0 votes

P_new= bsxfun(@times, LODF, P_old.');
P_new= bsxfun(@plus, P_new,P_old);

2 commentaires

Jip
Jip le 10 Déc 2013
Modifié(e) : Matt J le 10 Déc 2013
Although this code avoids the for loops, it is not faster, which is my purpose. Actually the code is much slower. Any other suggestions?
Matt J
Matt J le 10 Déc 2013
Modifié(e) : Matt J le 10 Déc 2013
For 32x32 data, I wouldn't be surprised if the for-loop was the fastest approach. For larger sizes, however, the vectorized approach will start to show superior performance, e.g.,
N=3200;
LODF=rand(N); P_old=rand(N,1);
tic;
P_new=zeros(size(LODF));
for k = 1:N
for l = 1:N
P_new(l,k) = P_old(l) + (LODF(l,k) * P_old(k));
end
end
toc;
%Elapsed time is 0.102201 seconds.
tic;
P_new= bsxfun(@times, LODF, P_old.');
P_new= bsxfun(@plus, P_new,P_old);
toc
%Elapsed time is 0.043591 seconds.
If you're not happy with the speed of your code, you should show us the slow part in its entirety. The small part you've shown is pretty fast, in and of itself.

Connectez-vous pour commenter.

Plus de réponses (2)

Jos (10584)
Jos (10584) le 10 Déc 2013

0 votes

for loops are pretty fast when you use pre-allocation
P_new = zeros(32,32) ;
for k = 1:32
for l = 1:32
P_new(l,k) = P_old(l) + (LODF(l,k) * P_old(k));
end
end
Jip
Jip le 10 Déc 2013

0 votes

Yes I know, I already did that.

Catégories

En savoir plus sur Loops and Conditional Statements dans Centre d'aide et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by