why when I use mvrnd to generate random vectors from a multivariate normal I always get small numbers in absolute value ?
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hi, why when I use mvrnd to generate random vectors from a multivariate normal I always get small numbers in absolute value (not larger than 4 or 5)? E.g.
mu=[0 0];
sigma=[1 0.4; 0.4 1];
r=10000; %number of simulated unobservables
epsilon=mvnrnd(mu,sigma,r);
Thanks
0 commentaires
Réponse acceptée
Vaclav Rimal
le 11 Déc 2013
The width of the distribution is ruled by the diagonal elements of sigma. If you want larger absolute values, try scaling sigma, e.g.
sigma = [10 4; 4 10];
2 commentaires
Vaclav Rimal
le 11 Déc 2013
Modifié(e) : Vaclav Rimal
le 11 Déc 2013
But when the variances are v=1.0, the standard deviations of both vectors are supposed to be sqrt(v)=1.0, so there is only a little probability that a value exceeds the number 5 you mentioned. (99.7 % should have absolute values less than 3*sqrt(v), which you can test by sum(abs(epsilon)<3).) You simply cannot have v=1.0 and large numbers in the result.
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Random Number Generation dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!