How I can find in a big matrix the elements that are simultaneously min on rows and max on columns?
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Sebastian Ciuban
le 15 Déc 2013
Commenté : Image Analyst
le 15 Déc 2013
For example I have
A=rand(50,50);
And I want to find the position and the values that are simultaneously min on rows and max on columns
4 commentaires
Image Analyst
le 15 Déc 2013
Exactly. So there will never be two minimums in the same row. And, for a given row, whatever column the row min does occur in will only be the max of the column it's in 1 time in 50. So most of the time he won't find any elements meeting the criteria. Perhaps you and I are interpreting what he said differently.
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Image Analyst
le 15 Déc 2013
This is very unlikely for a 5 by 5. I decreased the matrix to a 4 by 3 and it happens sometimes. Here's the code:
A = randn(4, 3)
[rowMins,colIndexOfMins] = min(A,[],2) % Within rows
[colMaxs, rowIndexOfMaxs] = max(A,[],1) % Within columns
rowMinMap = ismember(A, rowMins)
colMaxMap = ismember(A, colMaxs)
itsBoth = rowMinMap & colMaxMap
% Tell if there are any
if any(itsBoth(:))
[rows, cols] = find(itsBoth);
for k = 1 : length(rows)
message = sprintf('Row %d, column %d is both a row min and a column max',...
rows(k), cols(k));
helpdlg(message);
end
else
message = 'No element is both a row min and a column max';
warndlg(message);
end
In the command window for one case where it found such an element:
A =
-0.636128249660041 0.777003526719788 1.04858076053644
0.317851419059697 0.622393924172013 0.660707086367175
0.138047974449526 0.647380884516047 2.50877247318511
-0.710735074811226 -0.425631681660351 1.06345963904102
rowMins =
-0.636128249660041
0.317851419059697
0.138047974449526
-0.710735074811226
colIndexOfMins =
1
1
1
1
colMaxs =
0.317851419059697 0.777003526719788 2.50877247318511
rowIndexOfMaxs =
2 1 3
rowMinMap =
1 0 0
1 0 0
1 0 0
1 0 0
colMaxMap =
0 1 0
1 0 0
0 0 1
0 0 0
itsBoth =
0 0 0
1 0 0
0 0 0
0 0 0
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Plus de réponses (1)
Matt J
le 15 Déc 2013
rowmin=min(A,[],2);
colmax=max(A,[],1);
locations = bsxfun(@eq,A,rowmin) & bsxfun(@eq,A,colmax);
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