how to unzip files using external unzip software?

i have 50000 zip files.i need to unzip all those files and want to fetch .txt files alone from each zip files...any help..

 Réponse acceptée

Friedrich
Friedrich le 9 Jan 2014
Modifié(e) : Friedrich le 9 Jan 2014
Hi,
I would use JAVA to get what you want, e.g. the following example extract the .txt files in a zip files only (done with R2013b):
zipFile = org.apache.tools.zip.ZipFile('Untitled1.zip');
entries = zipFile.getEntries;
while entries.hasMoreElements
entry = entries.nextElement;
entryName = char(entry.getName);
[~,~,ext] = fileparts(entryName);
if strcmp(ext,'.txt')
inputStream = zipFile.getInputStream(entry);
fileOutputStream = java.io.FileOutputStream(fullfile(pwd,entryName));
streamCopier = com.mathworks.mlwidgets.io.InterruptibleStreamCopier.getInterruptibleStreamCopier;
streamCopier.copyStream(inputStream, fileOutputStream);
fileOutputStream.close;
inputStream.close;
end
end
zipFile.close
UPDATED VERSION FOR SCANNING A FOLDER FOR ZIP FILES AND PROCESS ALL OF THEM
zipfolder = 'C:\Users\fhempel\Desktop\tmp';
extractionfolder = 'C:\Users\fhempel\Desktop\tmp';
zipfiles = dir([zipfolder,'\*.zip']);
for i=1:numel(zipfiles)
zipFile = org.apache.tools.zip.ZipFile(fullfile(zipfolder,zipfiles(i).name));
entries = zipFile.getEntries;
while entries.hasMoreElements
entry = entries.nextElement;
entryName = char(entry.getName);
[~,~,ext] = fileparts(entryName);
if strcmp(ext,'.txt')
inputStream = zipFile.getInputStream(entry);
if ~exist(fullfile(extractionfolder,zipfiles(i).name(1:end-4)),'dir')
mkdir(fullfile(extractionfolder,zipfiles(i).name(1:end-4)))
end
fileOutputStream = java.io.FileOutputStream(fullfile(extractionfolder,zipfiles(i).name(1:end-4),entryName));
streamCopier = com.mathworks.mlwidgets.io.InterruptibleStreamCopier.getInterruptibleStreamCopier;
streamCopier.copyStream(inputStream, fileOutputStream);
fileOutputStream.close;
inputStream.close;
end
end
zipFile.close
end

8 commentaires

sandy
sandy le 9 Jan 2014
thanks..it works..but this is for one zip file..but i need to do this for 50000 files in a loop..looping is possible in this java code?
Friedrich
Friedrich le 9 Jan 2014
Modifié(e) : Friedrich le 9 Jan 2014
Sure, do what Walter posted befrore. You do an outer loop around my code and it should work fine. You would also need to adjust the
org.apache.tools.zip.ZipFile('Untitled1.zip');
call and the
fileOutputStream = java.io.FileOutputStream(fullfile(pwd,entryName));
call accordingly. See my updated post above.
sandy
sandy le 9 Jan 2014
i am not familiar with java code...looping also different in java syntax,help file in matlab for java syntax is not sufficient for this i think
sandy
sandy le 9 Jan 2014
Modifié(e) : sandy le 9 Jan 2014
??? Improper index matrix
reference.
Error in ==> zipfilecode at 6
zipFile =
org.apache.tools.zip.ZipFile(fullfile(zipfolder,zipfiles(i).name));
>>
Friedrich
Friedrich le 9 Jan 2014
Modifié(e) : Friedrich le 9 Jan 2014
The code works fine for me. From the error it seem that i is not what it is supposed to be. What value does the variable "i" have when the error occurs? And what dimensions has the variable "zipfiles"?
sandy
sandy le 9 Jan 2014
Modifié(e) : sandy le 9 Jan 2014
i=1 and i made some changes in the code in finding the .zip files using zipsearch() function as u can see below.my .zip files will be present inside many subfolders of a single main folder,so i used zipsearch(). also my output should be in a single folder where all .txt file should stored ther
zipfolder = 'C:\Users\fhempel\Desktop\tmp';
extractionfolder = 'C:\Users\fhempel\Desktop\tmp';
searchstr = '*.zip';
zipfiles = zipsearch(zipfolder, searchstr);
for i=1:numel(zipfiles)
zipFile = org.apache.tools.zip.ZipFile(fullfile(zipfolder,zipfiles(i).name));
entries = zipFile.getEntries;
while entries.hasMoreElements
entry = entries.nextElement;
entryName = char(entry.getName);
[~,~,ext] = fileparts(entryName);
if strcmp(ext,'.txt')
inputStream = zipFile.getInputStream(entry);
if ~exist(fullfile(extractionfolder,zipfiles(i).name(1:end-4)),'dir')
mkdir(fullfile(extractionfolder,zipfiles(i).name(1:end-4)))
end
fileOutputStream = java.io.FileOutputStream(fullfile(extractionfolder,zipfiles(i).name(1:end-4),entryName));
streamCopier = com.mathworks.mlwidgets.io.InterruptibleStreamCopier.getInterruptibleStreamCopier;
streamCopier.copyStream(inputStream, fileOutputStream);
fileOutputStream.close;
inputStream.close;
end
end
zipFile.close
end
I dont know the zipsearch functon and I dont know what it returns. But you need to adjust this line
zipFile = org.apache.tools.zip.ZipFile(fullfile(zipfolder,zipfiles(i).name));
Basically the argument needs to be the absolut path to the zip file you like to process, e.g. C:\some_folder\myzip.zip.
Since the output should be in one folder you can remove this three lines:
if ~exist(fullfile(extractionfolder,zipfiles(i).name(1:end-4)),'dir')
mkdir(fullfile(extractionfolder,zipfiles(i).name(1:end-4)))
end
Finally this one needs to be adjusted:
fileOutputStream = java.io.FileOutputStream(fullfile(extractionfolder,zipfiles(i).name(1:end-4),entryName));
I guess it should be:
fileOutputStream = java.io.FileOutputStream(fullfile(extractionfolder,entryName));
Please also update the extractionfolder variable to an existing folder on your machine. In addition please also update the zipfolder variable accordingly.
Hey, I was searching for this answer!, but I need to just extract the multiple zip files to another targer folder, so what changes should I make? since this will filter out non .txt files..

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Plus de réponses (2)

Walter Roberson
Walter Roberson le 9 Jan 2014

0 votes

1 commentaire

sandy
sandy le 9 Jan 2014
Modifié(e) : sandy le 9 Jan 2014
thanks...this s for fetching files in a dir or a specific folder..fetching inside each zip file is difficult here.any ideas..also.matlab unzip() function is faster than external program zip.exe ?..suggestion

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Hello, I think this answer is very useful for me.But I don't understand this two lines:
streamCopier = com.mathworks.mlwidgets.io.InterruptibleStreamCopier.getInterruptibleStreamCopier;
streamCopier.copyStream(inputStream, fileOutputStream);
Can you please be so kind to tell me what does this mean and what it will return?

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