Generate Random Sample of 0's and 1's

4 vues (au cours des 30 derniers jours)
Joe
Joe le 16 Jan 2014
Commenté : Suneesh le 16 Jan 2014
Hi guys,
how do I generate a random sample of 0's and 1's of size N, such that the probability of of 1 being chosen is p.
I can create a permutation however I can't seem to incorporate probability p into it. Plus, also is there a way I could quickly sum the components of the permutation.
Thanks,
Joe

Réponse acceptée

Suneesh
Suneesh le 16 Jan 2014
Modifié(e) : Suneesh le 16 Jan 2014
MATLAB has a function RANDSRC (part of the Comm Sys Tbx) which does this.
out = randsrc(1,N,[0 1; (1-p) p])
See documentation for the function to learn more about the usage.
  2 commentaires
Joe
Joe le 16 Jan 2014
thanks this is useful, how about summing the individual components, is there a function?
Suneesh
Suneesh le 16 Jan 2014

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Rajiv Ghosh-Roy
Rajiv Ghosh-Roy le 16 Jan 2014
How about
a = rand(1, N) < p
This creates a random vector of size N, and the < will return 1 if true, 0 if false.
  4 commentaires
Rajiv Ghosh-Roy
Rajiv Ghosh-Roy le 16 Jan 2014
Please consult the help for rand. rand(1, N) will generate a 1xN vector of random numbers uniformly distributed in [0, 1]. The probability that a number is in (0, p) is then p.
Suneesh
Suneesh le 16 Jan 2014
Modifié(e) : Suneesh le 16 Jan 2014
Joe, your problem may be stated as "Generate random numbers that have a Bernoulli distribution with the head(1) probability = p". There are several algorithms for generating random numbers and many start with generating random numbers that are uniformly distributed. This is what RAND does. The comparison " < p" owes to the inverse transform method of generating arbitrarily distributed random numbers from a uniform distribution. However, as far as I remember it should be "<=p". This method is standard in several text books on beginning probability theory. See also:
2. "Inverse Transform Method for simulating continuous random variables." in

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