Code bug with image algorithm
Afficher commentaires plus anciens
Hello there,
Here's a part of the code that I'm using to approximate an image and I'm kind of not understanding the problem with the last line. I'm suspecting there's something wrong with the datatype of m. The value of m is (sqrt(M)-1)/2 where M is the number of coefficients.
sizeImage = size(riceImage,1);
A = zeros(sizeImage);
sel = (sizeImage/2-m:sizeImage/2+sizeImage)+1;
A(sel,sel) = B(sel,sel);
1 commentaire
José-Luis
le 16 Jan 2014
It would be helpful if you posted the error you get.
Réponses (1)
Image Analyst
le 16 Jan 2014
Try this:
sizeImage = size(riceImage, 1); % Number of rows only (not # columns)
A = zeros(sizeImage); % rows by rows square image.
halfWidth = int32(sizeImage/2); % Round to nearest integer.
% The remaining code will go out of bounds and is nonsense.
% At least I don't understand the intent of it.
sel = (halfWidth -m : halfWidth + sizeImage)+1; % Maybe try end instead of sizeImage
A(sel,sel) = B(sel,sel); % No idea what this is supposed to do.
1 commentaire
Walter Roberson
le 17 Jan 2014
sizeImage/2+sizeImage is going to be greater than sizeImage so you are attempting to index outside the "A" that you defined.
Catégories
En savoir plus sur Image Quality dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!