Effacer les filtres
Effacer les filtres

Reduction of code lines

1 vue (au cours des 30 derniers jours)
Ayesha
Ayesha le 21 Jan 2014
Alright, so I've written this particular thing to blur an image and I've been wondering if I could reduce the number of lines or perhaps cut down the redundancies within this code especially the last line which copies one matrix to an other. Any over the top ideas would also be appreciated!
a=512;
b = a^2/16;
c=(sqrt(b)-1)/2;
ft11 = fftshift(fft2(myImage));
width = size(myImage,1);
F1 = zeros(width);
d = width/2;
e = (d-c:d+c)+1;
ft11(e,e)=F1(e,e);

Réponse acceptée

Walter Roberson
Walter Roberson le 21 Jan 2014
Modifié(e) : Walter Roberson le 21 Jan 2014
a = 512;
B = a/4;
c = (B-1)/2;
ft11 = fftshift(fft2(myImage));
width = size(myImage,1);
d = width/2;
e = (d-c:d+c)+1;
ft11(e,e) = 0;

Plus de réponses (1)

Amit
Amit le 21 Jan 2014
Its a good code. The only place I think there is a chance is
a=512;
b = a^2/16;
c=(sqrt(b)-1)/2;
ft11 = fftshift(fft2(myImage));
width = size(myImage,1);
%F1 = zeros(width); % You dont need to store these zeros
d = width/2;
e = (d-c:d+c)+1;
ft11(e,e)=zeros(e);
  1 commentaire
Amit
Amit le 21 Jan 2014
Modifié(e) : Amit le 21 Jan 2014
you might think of putting (d-c:d+c)+1 directly. However this might create more overhead, due to temporary storing those values (3 times). (I might be wrong about this)

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