How to use fprintf function.

I have been struggling with this problem all weekend. I am a very new user to MATLAB, and have a problem that I can't figure out. The problem is create a function that accepts a matrix of any dimension and prints the structure of the matrix.

Sample:

A=[5 4 5;3 1 6;1 2 3];
matrixPrint(A)
-       - 
|  5 4 5  |
|  3 1 6  |
|  1 2 3  |
-       -

B=[3;2;1];
matrixPrint(B)
-   -
|  3  |
|  2  |
|  1  |
-   -

C=3;
matrixPrint(C)

 -   -
|  3  |
 -   -

I can figure out how to create the 3x3 matrix, but i cant figure out how to apply this function to any size matrix. Any help is greatly appreciated.

[Azzi Abdelmalek]

What is matrixPrint ?

[Walter Roberson]

If you show your code then we can advise you on what you should change.

Answer 1

[Image Analyst]

I'd use a for loop and fprintf(). Hint:

fprintf('| ');
fprintf('%d ', A(1,:)); % Use %f if A is not integer.
fprintf(' |\n');

Answer 2

[Amit]

I am not gonna give you the solution (I will and many others like walter will correct your code, once you made an attempt). If I was given this problem, I would use some of these functions. You can see MAtlab documentation regarding these and then try writing it.

num2str , repmat and disp

Although this can be done by many approaches. Once you try some code, post it in your question (edit you question). Even if the code does not give you what you want, still we'll direct you modify it to get the right result. Matlab is not that difficult (overstatement), you just gotta try and learn :)

[Walter Roberson]

I would not use num2str() or disp() for this myself. But repmat() and horzcat() and fprintf() and transpose() and size()

[Amit]

Like I said there can be many approaches. The ultimate result will be the same. I prefer disp for simple cases where I do not have to worry to much about formatting.

Once he posts a code, I would love to see your code though. Always something to learn from Matlab Answers.

Answer 3

[Dog]

Thanks for the help guys, but I figured it all out. It was tough, but I learned a lot.

[Amit]

Isn't that fun! Figuring out how to do it with minimum help!

Answer 4

[Dog]

This is my code:

function [ M1 ] = matrixPrint( M ) %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% % % % % % %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

[row,col]=size(M);

if col<=1 fprintf(' -') for i=1:3*col fprintf(' ') end fprintf('- \n') for a=1:row fprintf('| ') for j=1:col fprintf('%2.0i ',M(a,j)) end fprintf('|\n') end

    fprintf(' -')
     for n=1:3*col
        fprintf(' ')
     end
      fprintf('- \n')
elseif col>1
fprintf(' -')
     for i=1:2*col
         fprintf('  ')
     end
fprintf(' - \n')
     for a=1:row
          fprintf('|  ')
     for j=1:col
          fprintf('%2.0i  ',M(a,j))
     end
fprintf(' |\n')
     end
    fprintf(' -')
     for n=1:2*col
          fprintf('  ')
     end
fprintf(' - \n')

else end

end

[Image Analyst]

Looks like a straightforward application of the code I gave you, except you made it a lot more complicated than it needed to be, like looping over columns instead of doing it the way I suggested. But still it looks like my hint was the catalyst that let you solve it, so can you mark my answer as accepted?