How to access randomly selected index in nested structures

I want to access intexes that are into a structure that are nested within another structure. I have this code working through every ith element, and I want to add to the code randomly selected values j. In my case j is from 1 to 365 day of the year.

for i=1:n
  fileName=structName(i).nestedStructName(j).name
  end

Any ideas?

Darina

Answer 1

[Amit]

Try something like this:

for i=1:n
  X = fieldnames(structName);
  n = length(X);
  fileName=structName(i).(X{randi(n)}).name;
end

The issue is that your nestedStucture has multiple fields and you wanna pick one randomly.

[Darina]

Thanks a lot! Works perfectly!

Answer 2

[Mischa Kim]

How about

fileName=structName(i).nestedStructName(randi(365,1)).name

Is this what you are looking for?

[Darina]

Hey thank you! But it keeps saying Reference to non-existent field 'demand_pattern'. I tried different things and I only get this error.

[Mischa Kim]

Does nestedStructName have 365 elements?

[Darina]

yes, why ?

[Darina]

Could the problem be in this -> structName(i) has 1xn struct while for j there are nestedStructName1,...,nestedStructName365 each has 1x1 struct?

[Mischa Kim]

Just before entering the for-loop add:

 [rS,  cS]  = size(structName)
 [rnS, cnS] = size(structName(rS).nestedStructName)

What do you get?

[Darina]

[rS,  cS]  = size(allFileMin)
 [rnS, cnS] = size(allFileMin(rS).demand_pattern)

the answer:

rS =

       1

cS =

      28

Reference to non-existent field 'demand_pattern'.

Error in Activity (line 136)
 [rnS, cnS] = size(allFileMin(rS).demand_pattern)

[Darina]

This happends because I only have nestedStructName1 to nastedStructName365 but not a single naestedStructName without index.

Answer 3

[Shivaputra Narke]

May this works,

for i=1:n j=1+round(364*rand(1)); fileName=structName(i).nestedStructName(j).name end

[Darina]

Hm, no it still gives the same error.. -.-