Effacer les filtres
Effacer les filtres

How to code this? Resampling of vector

2 vues (au cours des 30 derniers jours)
Lucas
Lucas le 5 Fév 2014
Commenté : Lucas le 5 Fév 2014
Hi all,
Currently I am trying to resample a signal by changing its signal frequency; The signal is given by time vector t and signal vector s. Example:
t=[ 1 2 3 4 5 6 7 8 9 10 11 12]
s=[3 3.5 3 5.5 2 2.5 3 5 7 2.5 3.5 4 ]
I want to create a vector s_new in which the sum of the values of s on the interval <0,4] is one element, the sum of interval <4,8] is an element etc, creating:
s_new= [15 12.5 17]
I have been toying around with histc but didnt succeed. Any ideas on coding this?
Thanks in advance! Lucas
  1 commentaire
Azzi Abdelmalek
Azzi Abdelmalek le 5 Fév 2014
Lucas commented
Thanks guys, but I actually want to use any resampling frequency, so the reshape command doesnt necessarily work (works only if old and new sampling times are integer multiples of each other). Thanks anyway!

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Réponse acceptée

Mischa Kim
Mischa Kim le 5 Fév 2014
Modifié(e) : Mischa Kim le 5 Fév 2014
For these straightforward time values, this will do
sum(reshape(s,4,3))
If t gets more complex you should be able to find a similar solution, though.

Plus de réponses (2)

David Sanchez
David Sanchez le 5 Fév 2014
s_new(1) = sum(s(find(s<4)))
s_new(2) = sum(s(find( (s<8)&(s>=4) )))
s_new(3) =sum(s(find( (s<12)&(s>=8) )))
...

Azzi Abdelmalek
Azzi Abdelmalek le 5 Fév 2014
Modifié(e) : Azzi Abdelmalek le 5 Fév 2014
t=[ 1 2.5 2.8 3 3.1 4 5 6 7 8 9 10 11 12];
s=[3 3.5 3.5 4 3 5.5 2 2.5 3 5 7 2.5 3.5 4 ]
ii=hist(t,[2 6 10]) % 2 is the middle of the interval [0,4];
ii2=cumsum(ii);
ii1=[1 ii2(1:end-1)+1];
out=arrayfun(@(ii,jj) sum(s(ii:jj)),ii1,ii2)
  1 commentaire
Lucas
Lucas le 5 Fév 2014
Thank you! Works great.

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