Crop image with a polygon
Afficher commentaires plus anciens
I'm new to matlab , i created a function that can detect an object in a picture , after this detection i want to corp the detected part (i drew a line around the detect area). i'm lost , i read some articles online which made a good use of the imcrop() function but i wasn't able to achieve my goal please help.
if true
%Get the bounding polygon of the reference image.
boxPolygon = [1, 1;... % top-left
size(boxImage, 2), 1;... % top-right
size(boxImage, 2), size(boxImage, 1);... % bottom-right
1, size(boxImage, 1);... % bottom-left
1, 1]; % top-left again to close the polygon
% Transform the polygon into the coordinate system of the target image. The transformed polygon indicates the location of the object in the scene.
newBoxPolygon = transformPointsForward(tform, boxPolygon);
%Display the detected object.
figure();
imshow(sceneImage);
hold on;
line(newBoxPolygon(:, 1), newBoxPolygon(:, 2), 'Color', 'R');
title('Detected Box');
end
This is my code i hope you direct me to the right track. Thank you
Réponses (3)
norliana khamisan
le 17 Mar 2015
1 vote
hello Elie, did you get the answer how to crop the detected part which is the boxPolygon? actually, I face same problem.could you help me how to crop the detected part (boxPolygon only).I've do some coding to crop the boxPolygon but it was error..i don't know why..thank you in advance.
1 commentaire
Image Analyst
le 18 Mai 2015
You should probably start your own question in a new/different thread. Post your image and show the desired output image.
Image Analyst
le 9 Fév 2014
I don't understand why you're doing. Why are you transforming points into a target image? What is the target image? If you just want to crops why don't you just call imcrop:
croppedImage = imcrop(yourImage, boxPolygon);
5 commentaires
Elie
le 9 Fév 2014
Image Analyst
le 10 Fév 2014
I don't have that toolbox so I can't follow along with the demo. I think you can do it better than me because of that.
Ravi Singh
le 17 Oct 2019
Hi Image Analyst,
I am not able to crop like you have suggested above for polygon cropping cropping. Imcrop only allows 4 coordinates which is min X, min Y, Height , Width but i the shape is polygonal it wont fitt while doing it with imcrop. Is there any other method to do the same??
Image Analyst
le 17 Oct 2019
The rectangle 1x4 vector is [minX, minY, width, height], which is not what you had. You can also do cropping with indexing to known rows and columns:
croppedImage = originalImage(row1:row2, column1:column2, :);
D_coder
le 21 Mar 2020
Can I get help for a somewhat similar question here. https://www.mathworks.com/matlabcentral/answers/512025-how-do-i-apply-a-window-on-an-image-to-keep-the-part-in-the-window-while-reduce-the-resolution-clar
Mehdi Saberioon
le 20 Mar 2015
you can use
roipoly
for cropping image in polygon format
3 commentaires
norliana khamisan
le 26 Mar 2015
means that, I need to replace function imcrop to roipoly?
I've try it,but still could not get the detected part(newBoxPolygon).
I change imcrop with roipoly like below:
bearing=roipoly(line(newBoxPolygon(:, 1), newBoxPolygon(:, 2), 'Color', 'r')); imshow(bearing);
dhia jamaa
le 18 Mai 2015
Modifié(e) : dhia jamaa
le 18 Mai 2015
- roipoly returns a binary image that you can use as a mask. so the result is a black and white image. the white region is the region that you selected. you can then replace the white region with the original photo.%%%%% matlab code
input = imread (I)
%coordinates of selected area
r=[40 204 267 102];
c=[136 125 210 219];
BW=roipoly(input,r,c);
%replacing white area with the desired image
out=zeros(size(BW,1),size(BW,2));
for i=1:size(BW,1)
for j=1:size(BW,2)
if BW(i,j)==1
out(i,j)=gray(i,j);
end
end
end
end
imshow(out)
i hope this is helpful
Image Analyst
le 18 Mai 2015
Instead of that for loop, you could have simply done
out = gray .* uint8(BW);
Catégories
En savoir plus sur Region and Image Properties dans Centre d'aide et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!