Being more concise with an IF statement

1 vue (au cours des 30 derniers jours)
Tom
Tom le 12 Fév 2014
Commenté : Tom le 12 Fév 2014
Hello,
Could someone tell me if there's a more concise way (I'm sure there is) of implementing the following:
if CN(count6,:) == 2
CN2(i,:) = bond_atom;
CN2(all(CN2==0,2),:)=[];
elseif CN(count6,:) == 3
CN3(i,:) = bond_atom;
CN3(all(CN3==0,2),:)=[];
elseif CN(count6,:) == 4
CN4(i,:) = bond_atom;
CN4(all(CN4==0,2),:)=[];
As you can see, I am creating matrices (CN2, CN3, CN4 etc...) using an IF criterion. However the criterion could be anything from 2 to ~20. So I wonder if I can summarise all the if's and elseifs in just a few lines, instead of having to repeat myself as I am doing here.
Kind regards,
Tom

Réponse acceptée

Iain
Iain le 12 Fév 2014
Modifié(e) : Iain le 12 Fév 2014
I'm assuming that CN only has one column.
number = CN(count6);
temp(1,:) = bond_atom;
temp(all(temp==0,2),:) = [];
CNoutput{number} = temp;
Replace CN4 with CNoutput{4}, etc.
  5 commentaires
Iain
Iain le 12 Fév 2014
You're right tehre is a subtlety that I'd assumed out of existence.
number = CN(count6);
CNoutput{number}(i,:) = bond_atom;
CNoutput{number}(all(CNoutput{number}==0,2),:) = [];
Tom
Tom le 12 Fév 2014
Thanks! That seems to be the ticket.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Performance and Memory dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by