Converting base 10 to base 2, dec2base help

So I am writing a script to convert a number from base 10 to base 2. I have written my own script, but I had trouble using dec2base. The function does not seem to work when I write something like

(i = dec2base(4, 2); and also fprintf('%g', i))

It outputs 494848. However, if I simply write dec2base(4, 2) without a semicolon the operation works, but the format is wrong.

Answer 1

[Jos (10584)]

X = dec2base(4,2)
whos X   % X is a character array!

fprintf('%g', X) % prints out ascii codes of the string!, Similar to ...
fprintf('%g', 'hello')  
fprintf('%s', X)  % use %s as a format string for character arrays

[Jarred]

Simply and concise!

Answer 2

[Walter Roberson]

bits_wanted = 16;
i = dec2base(4, 2, bits_wanted);
fprintf(i);

Answer 3

[Sagar Damle]

In MATLAB, either a comma(,) or a semi colon(;) separates two statements. Semi colon doesn't print the answer.

I think,you will require a 'number' in base 2 format and not a 'string'(i.e. character array).There are many functions in MATLAB to convert base 10 to base 2 of a number –

1. dec2base()

2. dec2bin()

3. de2bi()

4. dec2binvec()

However,outputs of these are are not in same format. Run this code on your computer for understaning purpose. See help about these functions in MATLAB.

Note : '0' represents ASCII value of zero(0) which is 48. So,

ans2 = dec2base(4,2) - '0'

is same as

ans2 = dec2base(4,2) – 48

Play with these functions! ENJOY!

% Program -
temp1 = dec2base(4,2)
ans1 = str2num(dec2base(4,2))
ans2 = dec2base(4,2) - '0'
temp2 = dec2bin(4)
ans3 = dec2bin(4) - '0'
temp3 = de2bi(4)
temp4 = de2bi(4,'right-msb')
ans4 = de2bi(4,'left-msb')
temp5 = dec2binvec(4)
ans5 = seqreverse(dec2binvec(4))
whos