having trouble with for loops
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Having Trouble...
'Sum of N^2 with N = 1 to 1,000 using a for loop'
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Plus de réponses (2)
Roger Stafford
le 13 Fév 2014
Here's a way to check your answer:
n = 1000;
s = n*(n+1)*(2*n+1)/6;
This gives you the same value as
s = sum((1:n).^2);
Alonso Mukendi Kalonji
le 29 Oct 2022
0 votes
a = 1;
n= 1000;
for i = 1: n
a = a+i^2
end
disp(a)
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