how to create array for these values i got?

 m=5;
u=[zeros(1,m-1) rand(1,1000)] ;
c=rand(m);
s=rand(m);
tmp=1;
while (tmp<=(length(u) - (m-1)))
        for i = 1:1:m
            x(i) = u(tmp + (i-1));       
            for j=1:1:m
                A(i,j)=exp(-0.5*((x(i)-c(i,j))./s(i,j)).^2);  
            end
            f(i)=min(A(i,j))
        end
        if (tmp==1000)
            break;
        end
        tmp=tmp+1;
end

i got the value of f (1x5) for 1000 times now i want to store these values in a array so that i get (1x5000) and again get the (1x5) from array 1000 times to use elsewhere.

Answer 1

[Chandrasekhar]

change the statement

f(i) = min(A(i,j));
to

f(tmp,i) = min(A(i,j));

[pinak parida]

the it creates a 1000x5 matrix

Answer 2

[Dishant Arora]

f = [];
for
   for
       %your code
   end
   f = [f,min(A)]
end

min(A(i,j)) doesn't make any sense as A(i,j) is going to be single element

[pinak parida]

did you run the code see it will not single value it is has 5 element and for 1000 tmies

Answer 3

[Andrei Bobrov]

m = 5;
idx = hankel(1:m,[m, m+1:numel(u)]);
x = reshape(u(idx),1,m,[]);
out = squeeze(min(exp(-bsxfun(@rdivide,bsxfun(@minus,x,c),s).^2/2),[],2));