area, stairs

32 vues (au cours des 30 derniers jours)
Hamed Amini
Hamed Amini le 20 Juil 2011
Modifié(e) : Bill Tubbs le 30 Mar 2024 à 18:47
Is there any property setting for 'area' function which generates the 'straits' for the boundary of the colored regions instead of 'plot' curves?

Réponse acceptée

Oleg Komarov
Oleg Komarov le 20 Juil 2011
% Random row input
x = 1:10;
y = rand(1,10);
% Normal area chart
subplot(3,1,1)
area(x,y)
% Stairs chart (non area)
subplot(3,1,2)
stairs(x,y)
% Stairs area
subplot(3,1,3)
x = [x;x];
y = [y;y];
area(x([2:end end]),y(1:end))
  1 commentaire
Hamed Amini
Hamed Amini le 20 Juil 2011
Very Clever! Thanks Oleg.

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Bill Tubbs
Bill Tubbs le 30 Mar 2024 à 4:33
Modifié(e) : Bill Tubbs le 30 Mar 2024 à 18:47
Building on Oleg's answer I wrote a function for doing the same thing with a stacked area plot. However, the data in the x and Y arguments here are aligned vertically in the rows, not horizontally in the columns.
function area_step_plot(x, Y)
assert(size(x, 2) == 1)
nx = size(x, 1);
Y = Y(1:nx-1, :); % final y-values are not used
ny = size(Y, 2);
X = [x x]';
X2 = X(2:end-1)';
Y2 = reshape(permute(cat(3, Y, Y), [3 1 2]), [], ny);
area(X2, Y2)
end
The Y argument can be a matrix of column vectors containing different data series.
x = (1:10)';
Y = rand(10, 3); % Note: last row is not plotted
area_step_plot(x, Y)

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