problem with the setdiff function

Hello!
i have a problem here
A = 2:.1:15
B=[9.4000 10.4000]
C=setdiff(A,B)
the elements 9.4000 and 10.4000 are still in the C
however,if B=[9.3000 10.3000] then the setdiff works fine,and the elements are not in the C.
any idea why this happens?

2 commentaires

Try
format hex
alex
alex le 17 Mar 2014
unfortunatelly the format hex is not working

Connectez-vous pour commenter.

 Réponse acceptée

Azzi Abdelmalek
Azzi Abdelmalek le 17 Mar 2014
Modifié(e) : Azzi Abdelmalek le 17 Mar 2014

0 votes

3 commentaires

alex
alex le 17 Mar 2014
thanks for the answer,but i can't figure out what to do with my problem..
Azzi Abdelmalek
Azzi Abdelmalek le 17 Mar 2014
Modifié(e) : Azzi Abdelmalek le 17 Mar 2014
Use some tolerance
A = 2:.1:15
B=[9.4000 10.4000 1000]
tol=0.0001
s=abs(bsxfun(@minus,A',B))<tol
[ii,jj]=find(s==1);
A(ii)=[]
alex
alex le 17 Mar 2014
thank you very much!
it works excellent!

Connectez-vous pour commenter.

Plus de réponses (1)

Jos (10584)
Jos (10584) le 17 Mar 2014
A = 2:.1:15
B = [9.4000 10.4000]
D = 2 ; % number of digits that should match (e.g. 1.231 = 1.229)
C = setdiff(round(A*10^D),round(B*10^D)) ./ (10^D)

Catégories

En savoir plus sur Loops and Conditional Statements dans Centre d'aide et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by