The Variable appears to change size on every loop iteration

10 vues (au cours des 30 derniers jours)
pooja
pooja le 19 Mar 2014
Commenté : Mahmoud Emad le 8 Avr 2020
[num_class,num_instance]=size(Outputs);
temp_Outputs=[];
temp_test_target=[];
for i=1:num_instance
temp=test_target(:,i);
if((sum(temp)~=num_class)&&(sum(temp)~=-num_class))
*temp_Outputs=[temp_Outputs,Outputs(:,i)];
temp_test_target=[temp_test_target,temp];*
end
end
Error: The Variable "temp_Outputs" appears to change size on every loop iteration
Question : I have No clue how to Preallocate it ?? Please help !!

Réponse acceptée

per isakson
per isakson le 19 Mar 2014
Modifié(e) : per isakson le 19 Mar 2014
This is not an error, it's a warning. It is inefficient to change size of a variable in a loop.
However, the if-statement makes it difficult to know the final size in advance, which is "needed" to preallocate.
IMO: don't care about the warning if the execution time is ok. It is possible to suppress it.
See:
  3 commentaires
per isakson
per isakson le 19 Mar 2014
Modifié(e) : per isakson le 19 Mar 2014
Check the links I provided. They are in the order from basic to advanced. There is no single sentence answer.
Mahmoud Emad
Mahmoud Emad le 8 Avr 2020
What if I had an execution time problem with a code very similar to this, my vector also is created by conactenation in a for loop, is there an efficient alternative ?

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by