Info

Cette question est clôturée. Rouvrir pour modifier ou répondre.

What's wrong with this code?

1 vue (au cours des 30 derniers jours)
Sam
Sam le 21 Mar 2014
Clôturé : MATLAB Answer Bot le 20 Août 2021
I am getting this error msg. Please find me the mistakes here.
In an assignment A(I) = B, the number of elements in B and I must be the same.
r=[2.0 3.1 3.5 3.65 3.84 3.95];
x=[];
x(1)=0.35;
f=@(x) r*x*(1-x);
N=40;
for t=1:N-1;
x(t+1)=f(x(t));
end
hold on
plot(x,'r-')

Réponses (2)

Joseph Cheng
Joseph Cheng le 21 Mar 2014
yes thats because you are including information that is not here and in your other posting that was flagged. but looks like you have it so we're all set?
  3 commentaires
Joseph Cheng
Joseph Cheng le 21 Mar 2014
only rude comment from me would be that posting on a forum for assignment questions involving things besides what type of functions to use, function errors, random matlab issues, and approaches to handling data is cheating. The Teaching Assistant or office hours should be where assignment related questions be asked.
Star Strider
Star Strider le 21 Mar 2014
And it’s not cheating to have MATLAB Answers do your homework for you?

Joseph Cheng
Joseph Cheng le 21 Mar 2014
Modifié(e) : Joseph Cheng le 21 Mar 2014
Were you attempting to do this?
r=[2.0 3.1 3.5 3.65 3.84 3.95];
x=[];
x(1,:)=0.35*ones(size(r));
f=@(x) r*x*(1-x);
N=40;
for t=1:N-1;
x(t+1,:)=f(x(t));
end
hold on
plot(x)
legend('r = 2.0','r = 3.1', 'r = 3.65')
Where the first value of x is 0.35? or you can re-write it such that the function
f=@(x,r) r*x*(1-x);
such that you write a for loop to cycle in the r you need.
  8 commentaires
Sam
Sam le 21 Mar 2014
Yes, but the graph I am getting for each individual r is completely different from when I use all the r values together if that make any sense to you.
Joseph Cheng
Joseph Cheng le 21 Mar 2014
no it doesn't make sense. how do they look different? shape? amplitude?

Cette question est clôturée.

Tags

Aucun tag saisi pour le moment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by