v = [0:1:100] without numbers that can be divided by 5

Hello,

I was wondering if there is any way to put in a vector going from 0 to 100 in steps of 1. The problem is the fact that I don't want any multiplications of 5 in this vector...

I want to do this because I made this efficiency plot (contourf), in which the efficiencies are plotted in steps of 1%. Every 1%-line is a dotted line, while every 5%-line is a full line with a label on it. The problem is that at every 5%-line, there still is a dotted 1%-line underneath it, so when I put my label in, the 5%-line breaks but the 1%-line shows up.

This is my code for plotting:

        %Graph title?
        header  = '(IM) Motor + Pump efficiency';
        %Which efficiency to plot?
        plotEfficiency = EffMotorHydrDriveIM;

        %PLOT NP EFFICIENCY
        figure;
        ax(1) = axes('Box','off','position',[0.08 0.08 0.77 0.73]);
        xlabel('Q [l/min]','fontsize',20)
        ylabel('P [Bar]','fontsize',20)
        title(header,'fontsize',30,'Units','Normalized','position',[0.55 1.15],'interpreter','latex') 
        colorbar('position',[0.92 0.08 0.02 0.73]);
        caxis([4,73]);
        hold on;  

        Vals = [0:1:100]; 
        contourf(QdriveIM,PdriveIM,plotEfficiency,Vals,'EdgeColor','k','LineWidth',1.2,'LineStyle',':');
        Vals = [0:5:100]; 
        [C,h] = contour(QdriveIM,PdriveIM,plotEfficiency,Vals,'EdgeColor','k','LineWidth',1.2);
        clabel(C,h,'Fontsize',10,'Color','k')
        hold off; 

        %PLOT N-T axes
        ax(2) = axes('Position',get(ax(1),'position'),...
                     'HitTest','off',...
                     'XAxisLocation','top',...
                     'YAxisLocation','right',...
                     'XLim',[NdriveIM(1,1) NdriveIM(1,end)],...
                     'YLim',[TdriveIM(1,1) TdriveIM(end,1)],...
                     'Color','none');
        xlabel(ax(2),'N [RPM]','fontsize',20)
        ylabel(ax(2),'T [Nm]','fontsize',20)

Answer 1

[Mischa Kim]

Andries, use the mod command:

 v = 0:1:100;
 v(mod(v,5)==0) = [];  % remove numbers divisible by 5

[AB]

Thank you very much, works like a charm !