Attempted to access c(4) ,,, lsqnonlin

2 vues (au cours des 30 derniers jours)
Michelle
Michelle le 26 Mar 2014
Commenté : Michelle le 26 Mar 2014
Hi i'm getting two errors
  • Attempted to access c(4); index out of bounds because numel(c)=3
  • Error in lsqnonlin Caused by: Failure in initial user-supplied objective function evaluation. LSQNONLIN cannot continue.
Any suggestions on how I can solve there errors ?
function V2mainprogram
clc;
clear;
format long;
fid=fopen('referencerawdata.txt','rt');
c=textscan(fid,'%f %f %f',1);
Ro=cell2mat(c(1,1));
Ri=cell2mat(c(1,2));
theta0=cell2mat(c(1,3));
theta0=theta0.*pi./180; %converting to radians
c=textscan(fid,'%f %f %f %f','Headerlines',1);
fclose(fid);
Pexp=cell2mat(c(1));
riexp=cell2mat(c(2));
lambdaexp=cell2mat(c(3));
Fexp=cell2mat(c(4));
options=optimset('largescale','off','MaxFunEvals',1e100,'TolFun',1e-30,'TolX',1e-30,'MaxIter',5e3,'Algorithm','levenberg-marquardt','Display','off');
w=[0.4679139345726910 0.3607615730481386 0.1713244923791704 0.4679139345726910 0.3607615730481386 0.1713244923791704];
ksi=[-0.2386191860831969 -0.6612093864662645 -0.9324695142031521 0.2386191860831969 0.6612093864662645 0.9324695142031521];
model='G';
iniconstants=[0.1 0.1 0.1];
RadLambexp=[riexp lambdaexp];
constants=lsqnonlin(@(x) errPF(x,RadLambexp,Pexp,Fexp,Ro,Ri,theta0,ksi,w,model),iniconstants,[],[],options);
fprintf('\n');
fprintf('G model constants\n');
fprintf('c1=%f\n',constants(1));
fprintf('c2=%f\n',constants(2));
fprintf('c3=%f\n',constants(3));
iniguess=[riexp lambdaexp];
RadLamb=lsqnonlin(@(x) errPF(constants,x,Pexp,Fexp,Ro,Ri,theta0,ksi,w,model),iniguess,[],[],options);
[Pressure,Force]=PF(constants,RadLamb,Ro,Ri,theta0,ksi,w,model); %uses optimized values to get theoretical pressure
RadLambG=RadLamb;
PressureG=Pressure;
ForceG=Force;
figure(1);
subplot(2,1,1);
plot(Pexp.*1000,riexp,('-r')); hold on;
plot(PressureFung.*1000,RadLambFung(:,1),'-k',PressureTH.*1000,RadLambTH(:,1),'--',PressureG.*1000,RadLambG(:,1),'--');
ylabel ('Inner radius [mm]');
xlabel('Inner pressure [KPa]');
subplot(2,1,2);
plot(Pexp.*1000,riexp,('-r')); hold on;
plot(PressureFung.*1000,RadLambFung(:,2),'-k',PressureTH.*1000,RadLambTH(:,2),'--',PressureG.*1000,RadLambG(:,2),'--');
ylabel ('Longitudinal stretch ratio');
xlabel('Inner pressure [KPa]');
end
%*****************************
function error=errPF(c,RadLamb,Pexp,Fexp,Ro,Ri,theta0,ksi,w,model)
[Pt,Ft]=PF(c,RadLamb,Ro,Ri,theta0,ksi,w,model);
errp=(Pt-Pexp).*Ri^2;
errf=(Ft-Fexp);
error=[errp;errf];
end
%***********************************
function[Pt,Ft]=PF(c,RadLamb,Ro,Ri,theta0,ksi,w,model)
ri=RadLamb(:,1);
lambda=RadLamb(:,2);
P=zeros(length(ri),1);
F=zeros(length(ri),1);
ro=sqrt(((Ro.^2-Ri.^2).*theta0)./(pi.*lambda)+ri.^2);
for i=1:length(ksi)
r=((ro+ri)./2+((ro-ri)./2).*ksi(i));%gd
R=sqrt(Ri.^2+(((pi.*lambda)./theta0).*(r.^2-ri.^2)));%gd
Ezz=0.5*((lambda.^2)-1);%gd
Ett=0.5*((((pi.*r)./(theta0.*R)).^2)-1);%gd
calcPartials=str2func(model);
[dWtt,dWzz]=calcPartials(c,Ett,Ezz);
P=P+w(i).*(((((pi.*r)./(theta0.*R)).^2).*dWtt)./r);%gd
F=F+w(i).*((2.*(lambda.^2).*dWzz)-(((pi.*r)./(theta0.*R)).^2).*dWtt).*r;%gd
end
Pt=((ro-ri)./2).*P;
Ft=pi.*((ro-ri)./2).*F;
end
%***************************************
function[dWtt,dWzz]=G(c,Ett,Ezz)
dWtt=1/2.*c(1).*((2.*c(2).*Ett)-(c(3).*(1./(((2.*Ett+1).^2).*(2.*Ezz+1)))).*(1./((2.*Ett+1).*(2.*Ezz+1)))).*(exp((c(2).*(Ett.^2))+(c(3).*(Ezz.^2))+((c(4)).*(1/4).*(((1./((2.*Ett+1).*(2.*Ezz+1))))-1.^2))));
dWzz=1/2.*c(1).*((2.*c(3).*Ezz)-(c(3).*(1./(((2.*Ezz+1).^2).*(2.*Ett+1)))).*(1./((2.*Ett+1).*(2.*Ezz+1)))).*(exp((c(2).*(Ett.^2))+(c(3).*(Ezz.^2))+((c(4)).*(1/4).*(((1./((2.*Ett+1).*(2.*Ezz+1))))-1.^2))));
end

Réponse acceptée

Alan Weiss
Alan Weiss le 26 Mar 2014
Well, I see in
function[dWtt,dWzz]=G(c,Ett,Ezz)
lines with
...+((c(4)).*...
If c has only three components, then these lines will definitely thow an error.
Alan Weiss
MATLAB mathematical toolbox documentation
  1 commentaire
Michelle
Michelle le 26 Mar 2014
Thank you !

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Historical Contests dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by