converting decimal matrix to binary matrix

I wish to convert a matrix of decimals to a matrix of binary numbers.

For example, if M = [ 1 25 34 9 ]

I then want, M = [ 00000001 00011001 00100010 00001001]

I got the output for the following matrix M=[6 5;1 3] from the below code.,but it doesn't work on the above matrix

   %   M=[6 5;1 3];
  %      b=dec2bin(M');
  %      b=b';
  %      b=str2num(b(:));
  %    b=reshape(b,8,2)'

 *Any help/pointers would be appreciated.*

Answer 1

[Azzi Abdelmalek]

M = [ 1 25 34 9 ]
out=cellstr(dec2bin(M,8))'

Answer 2

[Jos (10584)]

Do you want the output in strings, as cells, or as numbers?

M = [ 1 25 34 9 ]

Mstr  = dec2bin(M,8)   % char array
Mcell = cellstr(dec2bin(M,8)).' % cell array
Mnum  = dec2bin(M,8)-'0'   % numerical array

[Anu Sharma]

thanks a lot :) it worked !!

[Anu Sharma]

In the same way i applied your code for the image i.e.,reading the values of image and converting it to binary matrix.

 I=imread('lena.jpg');
 J=dec2bin(I(:),8)-'0';  % numerical array

but when i tried to access J it shows " Cannot display variables with more than 524288 elements."

Is there any solution

thanks in advanceee

[Jos (10584)]

Show parts of it

p = 1:100
disp(J(p,:))

But are you sure this is the most efficient way to look at your data?

[sam dhaka]

how can i make binary matrix from decimal matrix, suppose i have A=[2 3 4, 5 6 7, 1 2 1, 7 8 9] matrix and i want this like B=[1 1 1, 1 1 1, 0 0 0, 1 1 1]