How to make up the diagonal summation without for loop and with the fastest way!
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
A =
1 7 13
2 8 14
3 9 15
4 10 16
5 11 17
6 12 18
B =
1, (2+7), (3+8+13), (4+9+14), (5+10+15) ... (12+17), 18
How to make the B vector?
Vector-wise would be good to perform the enhancement of computational time?
0 commentaires
Réponse acceptée
Andrei Bobrov
le 1 Avr 2014
A =[ 1 7 13
2 8 14
3 9 15
4 10 16
5 11 17
6 12 18];
B = sum(spdiags(rot90(A)));
2 commentaires
Plus de réponses (3)
Azzi Abdelmalek
le 1 Avr 2014
Modifié(e) : Azzi Abdelmalek
le 1 Avr 2014
A =[ 1 7 13
2 8 14
3 9 15
4 10 16
5 11 17
6 12 18]
[n,m]=size(A);
B=fliplr(A);
out=zeros(1,m+n-1);
for k=-n+1:m-1
out(k+n)=sum(diag(B,k));
end
out=fliplr(out)
0 commentaires
Mischa Kim
le 1 Avr 2014
Modifié(e) : Mischa Kim
le 1 Avr 2014
Hyunchul, something like
fA = fliplr(A);
B = fliplr(arrayfun(@(i) sum(diag(fA,i)),-length(A(:,1))+1:length(A(1,:))-1));
0 commentaires
Sean de Wolski
le 1 Avr 2014
And just for fun (requires Image Processing):
B = zeros(size(A));
B(1) = 1;
B2 = bwdist(B,'cityblock')+1;
v = accumarray(B2(:),A(:))
Use Azzi's solution.
0 commentaires
Voir également
Catégories
En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!