Effacer les filtres
Effacer les filtres

need to plot value of tau for changing value of angles help

2 vues (au cours des 30 derniers jours)
Irenee
Irenee le 6 Avr 2014
Commenté : Irenee le 7 Avr 2014
clear % Homework D = diag(-rand(2,1)); % random diagonal matrix of 2 negatives eigenvalues v1 = rand(2,1); v2 = rand(2,1); %v1=v1/norm(v1); %v2=v2/norm(v2); V = [v1, v2]; r1=V(1,:); r2=V(2,:); %V = rand(2,2); % rotation matrix, the angle of rotation is pi/6 for k = 0:0.001:1/3 R = [cos(k*pi), -sin(k*pi); sin(k*pi), cos(k*pi)] k
r11 = r1*R;
r22 = r2*inv(R);
V1 = [r11;r22];
end %V1 = V*R A = V*D*inv(V); D1 = diag(-rand(2,1)); A1 = (V1)*(D1)*inv(V1); figure(1) p = (log(norm(inv(V)*V1)) + log(norm(inv(V1)*V)))/(-max(eig(A)) - max(eig(A1)))
plot(k,p) xlabel('k') ylabel('p')
can u help me to plot this ? the plot shows only a point in space thanks

Réponse acceptée

ragesh r menon
ragesh r menon le 7 Avr 2014
Here you are only storing last values of "k" and "p". And hence the plot shows a point. To modify the code, store value of k first. and the for loop should operate by calling "i". for example
for i=1:length(k)
R(i)=...
r11(i)=..
r22(i)=..
V1(i)=...
end.
this stores each of these values in an array and with these values you can find "p(i)"s. Now if you plot you should be able to meet your requirements
  1 commentaire
Irenee
Irenee le 7 Avr 2014
thanks a lot let me try this. Hope it will work.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Creating and Concatenating Matrices dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by