Matlab programming (line search)

function alpha=linesearch(t0,n,x,y,capacity)
ALPHA=.15
BETA=4
capacity1=capacity*.9;
a=0;
b=1;
r=(5^(1/2)-1)/2;
while(abs(a-b)>.00001)
 alphaleft=a+(1-r)*(b-a);
 alpharight=a+r*(b-a);
 zalphaleft=0;
 dleft=x+alphaleft*(y-x);
 dleft1=dleft./capacity1;
 for(i=1:n)
 zalphaleft(i)=t0(i)*dleft(i)*(1+ALPHA*(dleft1(i)^BETA));
 end
 zalphaleft=sum(zalphaleft);
 zalpharight=0;
 dright=x+alpharight*(y-x);
 dright1=dright./capacity1;
 for(i=1:n)
 zalpharight(i)=t0(i)*dright(i)*(1+ALPHA*(dright1(i)^4));
 end
 zalpharight=sum(zalpharight);
 if(zalphaleft<=zalpharight)
 b=alpharight;
 else
 a=alphaleft;
 end
end
alpha=(a+b)/2;

The error suggests:
Attempted to access t0(2); index out of bounds because numel(t0)=1.

Error in uesearch (line 18)
 zalphaleft(i)=t0(i)*dleft(i)*(1+ALPHA*(dleft1(i)^BETA));

May I ask how to fix this problem?

[Shashank Prasanna]

Can you format your code using the Code button?

[dpb]

for(i=1:n)
  zalphaleft(i)=t0(i)*...

You pass in t0 which apparently was a scalar and by name one presumes an initial value. But in the above loop you try to use it as a vector.

Only you know what it is you're actually trying to do, but that's your present coding problem.

Answer 1

[Image Analyst]

Maybe just say t0 instead of t0(i). Or t0 * i. This code does not have any comments, which is a sign of poor coding (you should scold whomever gave you this), so we don't really know what the intent is. But it's probably one or the other of the solutions I gave you.