how remove tow of three consecutive same values in a vector
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
DuckDuck
le 23 Avr 2014
Commenté : the cyclist
le 24 Avr 2014
I have two vectors like this
a=[1,2,3,1,1,1,2,3,2,3,1,1,1,1,2,3,3,3,2,2,1],
where * b * is id of * a *
b=[1,2,3,11,12,13,20,21,25,27,31,32,33,34,36,40,41,42,47,48,50]
what i want to achieve is to keep the midle element of three consecutive elements or the even element if te consecuence is more than 3 elements. i want to keep the b[4] or b[11] and b[13] also the b[16]. how to achieve this?? Can any body help?
9 commentaires
Geoff Hayes
le 23 Avr 2014
I don't understand "..but they are not consecutive in b". I thought that it was only the consecutive integers in a that we were concerned with?
Réponse acceptée
Azzi Abdelmalek
le 23 Avr 2014
a = [1,2,3,1,1,1,2,3,2,3,1,1,1,1,2,3,3,3,2,2,1];
b = [1,2,3,11,12,13,20,21,25,27,31,32,33,34,36,40,41,42,47,48,50];
c=diff(a)==0;
ii1=strfind([0 c 0],[0 1 1]);
ii2=strfind([0 c 0],[1 1 0])+1;
out=cell2mat(arrayfun(@(x,y) b(x+1:2:y),ii1,ii2,'un',0))
2 commentaires
the cyclist
le 24 Avr 2014
You did not mention anything about this in your original question. How were we to know this is what you needed?
Plus de réponses (1)
the cyclist
le 23 Avr 2014
This code is just terrible, but I think it does what you want.
a = [1,2,3,1,1,1,2,3,2,3,1,1,1,1,2,3,3,3,2,2,1];
b = [1,2,3,11,12,13,20,21,25,27,31,32,33,34,36,40,41,42,47,48,50];
d = [];
currentRunLength = 1;
for i = 2:numel(a)
if a(i)==a(i-1)
currentRunLength = currentRunLength+1;
if ((currentRunLength==2) && (i~=numel(a)) && a(i)==a(i+1)) || ((currentRunLength>=4) && mod(currentRunLength,2)==0)
d = [d,b(i)];
end
else
currentRunLength = 1;
end
end
3 commentaires
Geoff Hayes
le 23 Avr 2014
My mistake - I had read your a(i)==a(i-1) as ~= and so figured that a final check would be needed.
That being said, is it only the ids of the duplicates that are to be kept (from b) or should it be the ids of the single elements as well?
Voir également
Catégories
En savoir plus sur Creating and Concatenating Matrices dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!