Can you optimize this row matching code?

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Amir
Amir le 23 Avr 2014
Modifié(e) : Amir le 23 Avr 2014
Hi everyone,
I have a huge matrix on which I need to do some matching operation. Here's the code I have written and it works fine, but I think there is some room to make it more optimized or write another code that does the matching in less time. Could you please help me with that?
rowsMatched = find(bigMatrix(:, 1) == matchingRow(1, 1) & bigMatrix(:, 2) == matchingRow(1, 2) & bigMatrix(:, 3) == matchingRow(1, 3))
The problem with this code is that I cannot use the && operand. So, in case one of the columns do not match the program still checks the next condition. How do you think I can avoid this?
Thank you
  2 commentaires
Matt Kindig
Matt Kindig le 23 Avr 2014
Is matchingRow only a 1x3 vector? Or do you loop through all rows in matchingRow?
Can you post your full code?
Amir
Amir le 23 Avr 2014
Modifié(e) : Amir le 23 Avr 2014
It's just a 1x3 vector in this case, but it could be up to 1 x 10 (in case I had a bigMatrix with the size, say, (1m, 10). However, I still don't know how to make the code that much flexible being able to do the matching for a 1 x 3 up to 1 x 10 matchingRow vector.

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Réponse acceptée

Amir
Amir le 23 Avr 2014
Modifié(e) : Amir le 23 Avr 2014
Here's the solution:
rowsMatched = find(all(bsxfun(@eq, bigMatrix, matchingRow),2))

Plus de réponses (1)

Matt Kindig
Matt Kindig le 23 Avr 2014
How about this approach? Is it fast enough?
%bigMatrix is MxN, matchingRow is 1xN
rowsMatched = find(ismember( bigMatrix(:,1:3), matchingRow, 'rows'));
  1 commentaire
Amir
Amir le 23 Avr 2014
No this is slower.

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