MATLAB Answers

0

Extract data from cell array based on date and back into dataset

Asked by mashtine on 6 May 2014
Latest activity Commented on by Geoff Hayes
on 6 May 2014
Hi everyone,
I have a cell array with date (converted using datenum) and data values in other columns. I would like to use this cell arrya as a reference point from which I can extract data (say from col 5) based on matching times.
For instance, the larger dataset can be:
724642 605 250 10.8024000000000 240
724643 605 250 11.8312000000000 230
724644 605 240 11.3168000000000 230
724645 605 240 10.8024000000000 230
and the lookup dataset can be:
724642 605 13
724644 605 22
And the result I would like would be the values from the lookup dataset and in the last column, the extracted data from the corresponding date in the 5 col of the larger dataset:
724642 605 13 240
724644 605 22 230
I have used ismember and find but the indices returned to not work as the two cell arrays will have different sizes and thus after finding the matching indices (fairly easy) I cannot just plug that in to extract the data as dates may not be found in one dataset.
Any help would be appreciated! Many thanks.

  0 Comments

Sign in to comment.

1 Answer

Answer by Geoff Hayes
on 6 May 2014
 Accepted Answer

Hi Masao - A combination of the ismember and removing of zeros may work. If A is your first matrix (larger data set) and B is your second matrix (lookup dataset), then
[isInA,whereInA]=ismember(B(:,1),A(:,1))
will return the isInA indicating which elements of B are in A (1) and which elements aren't (0). The whereInA will indicate what those indices are in A. If all elements of B are in A then there is no problem and we could use the following to append the final column of A onto B:
B(isInA,4) = A(whereInA,5);
But if there is an element of B not in A then there is a zero in the same row of each of the isInA and whereInA matrices. Using that fact, and that zero indices on the left-hand side of the assignment will be ignored, we can do:
% remove the zeros from whereInA
whereInA(whereInA==0) = [];
% append the column of A onto B for those elements of B in A wrt time
B(isInA,4) = A(whereInA,5);
I added some dummy rows to your example of B (so that the first and third rows of this updated matrix would not match wrt time in A) and the result was as expected - the two rows that did match in A had their fourth column updated with the fifth column of A.
Geoff

  2 Comments

You have saved the day and my sanity! Many thanks Geoff

Sign in to comment.