how to make a matrix grow inside a parfor loop?

2 vues (au cours des 30 derniers jours)
kira
kira le 7 Mai 2014
Commenté : kira le 9 Mai 2014
Hi, i would like to do this in a parfor loop:
S=[];
for n=in:fin
[s,trueorfalse]=somefunction(someinput);
if trueorfalse
S=[S;s];
end
end
I cannot preallocate because i don't know how much big S will be. I tried some thing but nothing worked so far.
Hope you could help me.

Réponse acceptée

Edric Ellis
Edric Ellis le 7 Mai 2014
Modifié(e) : Edric Ellis le 7 Mai 2014
You should be able to do this. For example, the following works correctly:
S = [];
parfor idx = 1:10
r = rand();
if r > 0.5
S = [S, r];
end
end
  3 commentaires
Edric Ellis
Edric Ellis le 8 Mai 2014
Did you try precisely that code? That code works correctly all the way back even to MATLAB R2008a. Which version did you try it in?
kira
kira le 9 Mai 2014
hi, i tried my original code again, changing for by parfor an now it works... ?_?
thanks to all for your help...

Connectez-vous pour commenter.

Plus de réponses (1)

Brian B
Brian B le 7 Mai 2014
You could make S a cell array in the loop, then create a matrix afterward:
somefunction = @(x)deal(x,rand(1)<0.3);
S=cell(100,1);
parfor n=1:100
[s,trueorfalse]=feval(somefunction, n);
if trueorfalse
%S=[S;s];
S{n} = s;
end
end
S = cell2mat(S);
  1 commentaire
kira
kira le 7 Mai 2014
i could this with S=sparse(fin,dim), but variable fin is very big (O(2^m))

Connectez-vous pour commenter.

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by