Integration of velocity not working, creating zeros

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Adrienne
Adrienne le 15 Mai 2014
Modifié(e) : dpb le 16 Mai 2014
%%Calculation of Velocity and Acceleration
v(i,1)= trapz(jh(i,1));
a(i,1)= trapz(v(i,1));
This is what I am using for differentiation. But both of these are coming out in the workspaces as zero... I don't know what this is. jh is jump height, there are numbers for this

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dpb
dpb le 15 Mai 2014
trapz is an trapezoidal INTEGRATION routine, not differentiation
doc trapz
doc diff
  2 commentaires
Adrienne
Adrienne le 15 Mai 2014
sorry i did mean integration and it is not working
dpb
dpb le 15 Mai 2014
Modifié(e) : dpb le 16 Mai 2014
"not working" is NEVER sufficient explanation for a problem.
But, if v is velocity and a acceleration, then you're going the wrong way physically.
a=dv/dt --> v=Int(a dt)
As for the zero result, looks like jh(i,1) is a single point so there's nothing to integrate over (even though you need to be differentiating instead it would appear).

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