Integration of velocity not working, creating zeros

2 vues (au cours des 30 derniers jours)
Adrienne
Adrienne le 15 Mai 2014
Modifié(e) : dpb le 16 Mai 2014
%%Calculation of Velocity and Acceleration
v(i,1)= trapz(jh(i,1));
a(i,1)= trapz(v(i,1));
This is what I am using for differentiation. But both of these are coming out in the workspaces as zero... I don't know what this is. jh is jump height, there are numbers for this

Réponse acceptée

dpb
dpb le 15 Mai 2014
trapz is an trapezoidal INTEGRATION routine, not differentiation
doc trapz
doc diff
  2 commentaires
Adrienne
Adrienne le 15 Mai 2014
sorry i did mean integration and it is not working
dpb
dpb le 15 Mai 2014
Modifié(e) : dpb le 16 Mai 2014
"not working" is NEVER sufficient explanation for a problem.
But, if v is velocity and a acceleration, then you're going the wrong way physically.
a=dv/dt --> v=Int(a dt)
As for the zero result, looks like jh(i,1) is a single point so there's nothing to integrate over (even though you need to be differentiating instead it would appear).

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Numerical Integration and Differentiation dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by