fminunc stopped because it exceeded the function evaluation limit, options.MaxFunEvals = 100 (the default value).

what should i do if i get this kind of error?

Answer 1

[George Papazafeiropoulos]

Define the objective function by setting its output with the opposite sign as follows:

function F=fun(x)

F=-0.2662*x.^6+48.19*x.^5-3424.2*x.^4+121708*x.^3-2*exp(6)*x.^2+2*exp(7)*x-6*exp(7);

F=-F;

end

The initial function that you presented does not have a finite global minimum, it tends to -inf due to the negative sign at the coefficient of x^6. The above function has a global minimum, so if you execute the code:

x0 = 1;

[x, fval] = fminunc (@fun,x0)

then the algorithm finds the local minimum of -fun, therefore the global maximum of fun.

[hizaki]

SIR THANK YOU SO MUCH it reallyworked! :)))