Help me how to calculate sum of series ?

69 vues (au cours des 30 derniers jours)
Nguyen Trong Nhan
Nguyen Trong Nhan le 27 Mai 2014
help me how to calculate the sum of a series in Matlab. (for example 2 series in the picture)
  1 commentaire
chadi cream
chadi cream le 22 Déc 2017
Modifié(e) : Walter Roberson le 22 Déc 2017
symsum((sqrt(n+1) - sqrt(n-1))/n^(3/4),n,1,inf)
vpa(ans)
=5.0311555338624769245497524622442

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Réponses (4)

rifat
rifat le 27 Mai 2014
Modifié(e) : rifat le 27 Mai 2014
You can not add infinite number of terms. If the sum is a converging sum, then you can add a large number of terms (e.g. n=5000) to get a satisfactory result.
n=5000;
series1=0;
series2=0;
for i=1:n
p=(((i+1)/i)^i)/(i^2);
series1=series1+p;
p=(sqrt(i+1)-sqrt(n-1))/(i^.75);
series2=series2+p;
end
  2 commentaires
Nguyen Trong Nhan
Nguyen Trong Nhan le 27 Mai 2014
what's about the symsum function ?
Sandie Nhatien Vu
Sandie Nhatien Vu le 5 Août 2016
@Rifat ahmed is it possible to write a script using vectorized computation instead of the for-loop for that sum of series?

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Roger Wohlwend
Roger Wohlwend le 27 Mai 2014
n = 1 : 10^6;
sum(((n+1)./n).^n./n.^2)
sum((sqrt(n+1) - sqrt(n-1))./n.^(3/4))
  2 commentaires
Nguyen Trong Nhan
Nguyen Trong Nhan le 27 Mai 2014
what's about the symsum function ?
chadi cream
chadi cream le 22 Déc 2017
Modifié(e) : Walter Roberson le 5 Juin 2021
syms n;
f=1/n^2*((n+1)/n)^n
symsum(f,n,1,inf)
vpa(ans) = 3.550777333936337795612455939406

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Perwez Alam
Perwez Alam le 4 Déc 2018
How to write editer command to plot (t,g)
Please help me.
thanking You

Kokou Moutchou
Kokou Moutchou le 1 Mai 2018
sqrt(6*((1/1^2)+(1/2^2)+(1/3^2)+...+(1/n^2(

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