for loop indexing and skip numbers

Hi,

I need to include for loop in MATLAB to start with 2:13. But I need to start with 2,3,4 and skip 5 and again 6,7,8 and skip 9 and 10,11,12 until 13.

How can I implement this is for loop?

Many thanks in advance.

Answer 1

[Roger Stafford]

You can also use

 ix = floor((4*(1:n)+2)/3);

where n is the desired length of the output.

[Damith]

Thanks. I appreciate it.

Answer 2

[the cyclist]

for n = [2 3 4 6 7 8 13]
  disp(n)
end

[Damith]

Thanks. But if I use upto 10000, how can I formulate this? For example,

2,3,4,6,7,8,10,11,12,14,15,16.....10000.

Thanks again.

[Image Analyst]

A nice feature that not many people know about, but more should. It's good that you pointed it out. +1 vote.

[the cyclist]

idx = setdiff(2:10000,5:4:10000);

for ii = idx
  disp(ii)
end

[Damith]

Thanks. It worked.

[Abraxas]

I've been searching 2 days for this answer! Thank you so much!

Answer 3

[the cyclist]

Yet another method:

idx = bsxfun(@plus,[1 2 3]',1:4:100)

for ii = idx(:)
  disp(ii)
end

[Damith]

Thanks. it's working too.

Answer 4

[the cyclist]

Yet another method:

idx = filter([1 1 1 1],[1 1 1 0],1:100)+1

[Damith]

Thanks.